Question

我试图通过一个简单的例子来描述问题。可以说，我有一个语法，看起来像这样：

Model:
    rules+=Rule*;

Rule:
    View | Element;

Element:
    'element' name=ID members+=Member members+=Member* 'end';

View:
    'view' name=ID 'for' forElement=[Element] 
    forMembers+=[Member] forMembers+=[Member]* 'end';

Member:
    'member' name=ID;

这种语言的一个简单例子是：

// Element is where the Members are instantiated
element Foo
    member bar
    member foobar
    member barfoo
    member something
end

// Views only reference the members by simple name
view FooView for Foo
    bar 
    foobar 
    something
end

我有forMembers的{{1}}属性的自定义范围提供程序：

View rule

到目前为止一切都很好，我的问题来到这里：

我还有一个格式化程序，我无法为引用的class MyDslScopeProvider extends AbstractDeclarativeScopeProvider { def scope_View_forMembers(View view, EReference reference) { Scopes.scopeFor(view.forElement.members); } }添加规则：

Member

如您所见，我已为class MyDslFormatter extends AbstractDeclarativeFormatter { @Inject extension MyDslGrammarAccess override protected void configureFormatting(FormattingConfig c) { // Rules for element: line breaks, indentation increment and decrement c.setLinewrap(1).after(elementAccess.nameAssignment_1) c.setLinewrap(1).after(elementRule) c.setIndentationIncrement.after(elementAccess.nameAssignment_1) c.setIndentationDecrement.before(elementAccess.endKeyword_4) // Rules for view: line breaks, indentation increment and decrement c.setLinewrap(1).after(viewAccess.forElementElementCrossReference_3_0) c.setLinewrap(1).after(viewRule) c.setIndentationIncrement.after(viewAccess.forElementElementCrossReference_3_0) c.setIndentationDecrement.before(viewAccess.endKeyword_6) //formatting for Member rule, only works, where Member rules are instantiated. c.setLinewrap(1).after(memberRule) } }和Element规则以及View规则设置了格式。但是，Member规则的格式仅适用于实例化的（例如：Member声明）。当我运行这个格式化程序（ Ctrl + Shift + F ）时，我得到以下格式：

Element

但是我想让所有引用的成员都在一个新的行中。 如何实现这一目标？非常感谢任何帮助！

Answer 1

在View规则中引用了成员。你必须在这些成员之后设置linewrap：

    c.setLinewrap(1).after(viewAccess.forMembersAssignment_4)
    c.setLinewrap(1).after(viewAccess.forMembersAssignment_5)

引用元素的XText格式规则

1 个答案: