Question

我有一个差不多完成的PHP文档。但是，在将表单通过电子邮件发送给收件人之前，我需要删除所有空字段。下面，我将包含选择所有表单字段以准备发送的代码。我如何对此进行编码以仅选择从用户输入数据的元素？

//Gathering Data
    $email_body = "";
    $email_body = $email_body . "Name: " . $name . "<br />";
    $email_body = $email_body . "Address: " . $address . "<br />";
    $email_body = $email_body . "City: " . $city . "<br />";
    $email_body = $email_body . "State: " . $state . "<br />";
    $email_body = $email_body . "Zip: " . $zip . "<br />";
    $email_body = $email_body . "Home Phone: " . $hmP . "<br />";
    $email_body = $email_body . "Work Phone: " . $wrkP . "<br />";
    $email_body = $email_body . "Cell Phone: " . $cellP . "<br />";
    $email_body = $email_body . "Fax #: " . $fx . "<br />";
    $email_body = $email_body . "Email: " . $email . "<br /><br />";
    $email_body = $email_body . "Service Type: " . $service . "<br />";

Answer 1

正如评论所指出的那样，你可以这样做：

$email_body = "";
$email_body .= !empty($name) ? $email_body . "Name: " . $name . "<br />" : '';
$email_body .= !empty($address) ? $email_body . "Address: " . $address . "<br />" : '';
$email_body .= !empty($city) ? $email_body . "City: " . $city . "<br />" : '';
$email_body .= !empty($state) ? $email_body . "State: " . $state . "<br />" : '';
$email_body .= !empty($zip) ? $email_body . "Zip: " . $zip . "<br />" : '';
$email_body .= !empty($hmP) ? $email_body . "Home Phone: " . $hmP . "<br />" : '';
$email_body .= !empty($wrkP) ? $email_body . "Work Phone: " . $wrkP . "<br />" : '';
$email_body .= !empty($cellP) ? $email_body . "Cell Phone: " . $cellP . "<br />" : '';
$email_body .= !empty($fx) ? $email_body . "Fax #: " . $fx . "<br />" : '';
$email_body .= !empty($email) ? $email_body . "Email: " . $email . "<br /><br />" : '';
$email_body .= !empty($service) ? $email_body . "Service Type: " . $service . "<br />" : '';

这使用三元运算符来确保没有空值附加到电子邮件字符串

你也可以将它包装在一个函数中：

function buildEmail($emailParts) {
   $retString = '';
   foreach ($emailParts as $part) {
        $retString .= !empty($part['value']) ? $part['label'] . ' ' . $part['value'] . '<br />' : '';
   }
   return $retString;
}

$emailParts = array(
    array('label' => 'Name:', 'value' => $name),
    array('label' => 'Address:', 'value' => $address)
    ...
);
$emailBody = buildEmail($emailParts);

Answer 2

这是我会采取的方法。做一个可以在输出时过滤的设置数组。

    // I just isset + !empty, but you can specify is_numeric(),
    // preg_replace() etc...
    $_settings[]    =   (isset($name) && !empty($name))? "Name: " . $name:'';
    $_settings[]    =   (isset($city) && !empty($city))? "City: " . $city:'';
    $_settings[]    =   (isset($state) && !empty($state))? "State: " . $state:'';
    $_settings[]    =   (isset($zip) && !empty($zip))? "Zip: " . $zip:'';
    $_settings[]    =   (isset($hmp) && !empty($hmp))? "Home Phone: " . $hmp:'';
    $_settings[]    =   (isset($wrkP) && !empty($wrkP))? "Work Phone: " . $wrkP:'';
    $_settings[]    =   (isset($cellP) && !empty($cellP))? "Cell Phone: " . $cellP:'';
    $_settings[]    =   (isset($fx) && !empty($fx))? "Fax #: " . $fx:'';
    $_settings[]    =   (isset($email) && !empty($email))? "Email: " . $email:'';
    $_settings[]    =   (isset($service) && !empty($service))? "Service Type: " . $service:'';

    // Remove empties. You don't really need to remove empties,
    // it's a force of habit to filter an array...
    $_settings  =   array_filter($_settings);

    // If array is still populated, implode and continue on.
    if(!empty($_settings)) {
            $email_msg  =   implode("<br />\r\n",$_settings);
            // rest of code here
        }

Answer 3

如果你知道你的变量名，那么你也可以用更复杂的方法来解决你的问题.2。想节省工作......

您可以创建一个包含所有变量名称及其“描述”的数组，例如：

$variables = array(
  "name"    => "Name: ",
  "address" => "Address: ",
  "city"    => "City: ",
  "state"   => "State: ",
  "zip"     => "Zip: ",
  "hmP"     => "Home Phone: ",
  "wrkP"    => "Work Phone: ",
  "cellP"   => "Cell Phone: ",
  "fx"      => "Fax #: ",
  "email"   => "Email: ",
  "service" => "Service Type: " 
  );

然后使用每个元素作为变量名循环遍历数组，方法是使用第二个$询问它是!empty还是isset像Fred -ii-那样建议：

foreach($variables as $var => $description)
{
  if(isset($$var))
  {
    $email_body .= $description . $$var . "<br />";
  }
}

PHP表单 - 在发送之前删除项目

3 个答案: