Question

想象一下食物清单。用户搜索食物并显示与此匹配的所有食物的列表。

例如，用户搜索'apple'，程序返回'red apple'，'green apple'等。

for (int i = 0; ; i++) {
     if (foodNames[i].contains(searchTerm){
         foodChoice1 = foodName[i];
         break;
         // then print food name
     }
}

如何扩展以显示列表中的多个食物名称？代码只是当场嘲笑，可能不起作用，只是为了展示一个例子。

Answer 1

如何使用Set<String>存储结果并与小写字母进行比较？

String[] foods = {
    "Red apple", "Green APPLE", "Apple pie", 
    "Lobster Thermidor Sausage and SPAM"
};
String query = "apple";
String queryTLC = query.toLowerCase();
// sorting result set lexicographically
Set<String> results = new TreeSet<String>();
for (String food: foods) {
    if (food.toLowerCase().contains(queryTLC)) {
        results.add(food);
    }
}
System.out.println(results);

<强>输出

[Apple pie, Green APPLE, Red apple]

Answer 2

试试这个：

List<String> matchingFood = new ArrayList<String>();
for (int i = 0; i < foodNames.length; i++) {
    if (foodNames[i].contains(searchTerm)
    {
         matchingFood.add(foodName[i]);
    }
}
System.out.println("Food matching '" + searchTerm + "' :");
for (String f : matchingFood)
{
    system.out.prinln(f);
}

Answer 3

你可以简单地使用它：

String[] strArray = {"green apple", "red apple", "yellow apple"};
for (String s : strArray)
    if (s.contains("apple"))
        System.out.println(s);

如何在字符串数组中显示匹配字符串列表？

3 个答案: