Question

我正在尝试设置一个简单的用户输入菜单（非gui），如下所示：

如果用户输入0：

已加载文件。
菜单出现选项1-5提示另一个用户输入从1到5.现在，在这里，在第一个用户之后输入，一些处理完成。然后我想问问用户用于第二个用户输入。这应该持续到用户输入为止 6岁或以上。

否则（如果用户未输入0）打印＆＃34;错误退出。请重启程序。＆＃34;

这就是我所拥有的：

import csv

# Load input file:
choiceloading = input('Please enter 0 to load the input file: ')
if choiceloading == 0:
    with open('eggs.csv', 'rb') as csvfile:
    spamreader = csv.reader(csvfile, delimiter=' ', quotechar='|')
    for row in spamreader:
        print ', '.join(row)

print ("   M A I N - M E N U")
print ("1. Action 1")
print ("2. Action 2")
print ("3. Action 3")
print ("4. Action 4")
print ("5. Action 5")

# Get user input:
choice = raw_input('Enter choice [1-5] : ')

# Convert input (number) to int type:
choice = int(choice)

# Perform action based on menu-option selection by user:
if choice == 1:
    print ("Action 1...")
    #processing #1 is done here
elif choice == 2:
    print ("Action 2...")
    #processing #2 is done here
elif choice == 3:
    print ("Action 3...")
    #processing #3 is done here
elif choice == 4:
    print ("Action 4...")
    #processing #4 is done here
elif choice == 5:
    print ("Action 5...")
    #processing #5 is done here
else:
    print ("Invalid entry. You should choose 1-5 only. Program exiting.....please restart it and try again.")
else:
    print ("Invalid entry. You should choose 0 to load the file. Program exiting.....please restart it and try again.")

目前，该程序只接受1个用户输入。处理完毕后，退出。恩。如果用户输入3，并且3的处理完成，则程序将退出。

但是，我想允许用户输入1,2,4,5来处理1,2,4,5。然后他们应该输入＆gt; 5退出。

问题：处理后，如何更改此代码以允许用户输入剩余的输出？

Answer 1

最简单的方法是在循环中添加处理，如下所示：

while True:
    # Get user input:
    choice = raw_input('Enter choice [1-5] : ')

    # Convert input (number) to int type:
    choice = int(choice)

    if choice == 1:
        print ("Action 1...")
        #processing #1 is done here
    elif choice == 2:
        print ("Action 2...")
        #processing #2 is done here
    elif choice == 3:
        print ("Action 3...")
        #processing #3 is done here
    elif choice == 4:
        print ("Action 4...")
        #processing #4 is done here
    elif choice == 5:
        print ("Action 5...")
        #processing #5 is done here
    else:
        print ("Invalid entry. You should choose 1-5 only. Program exiting.....please restart it and try again.")
        # Add sys.exit() (will have to add 'import sys' to top
    else:
        print ("Invalid entry. You should choose 0 to load the file. Program exiting.....please restart it and try again.")
        # Add sys.exit()

Python多个用户输入 - 在退出之前浏览所有输入

1 个答案: