我想将图片上传到我的appengine 因此,我有了诱惑MyImage(来自互联网上的另一个主题):
@Entity
public class MyImage implements Serializable
{
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
private Long id;
static int ID=1;
private String name;
Blob image;
public MyImage()
{
id=(long) ID++;
}
public MyImage(String name, Blob image)
{
this.name = name;
this.image = image;
id=(long) ID++;
}
// JPA getters and setters and empty contructor
// ...
public Blob getImage()
{
return image;
}
public void setImage(Blob image)
{
this.image = image;
}
}
我有这个代码(也来自internt): (它是jsp页面使用的servlet。)
public class UploadImg extends HttpServlet
{
/**
*
*/
private static final long serialVersionUID = 1L;
public void doPost(HttpServletRequest req, HttpServletResponse res)
{
// Get the image representation
try
{
HelpDebug.msg="start of servlet";
ServletFileUpload upload = new ServletFileUpload();
FileItemIterator iter = upload.getItemIterator(req);
FileItemStream imageItem = iter.next();
InputStream imgStream = imageItem.openStream();
HelpDebug.msg="after open stream";
// construct our entity objects
Blob imageBlob = new Blob(IOUtils.toByteArray(imgStream));
MyImage myImage = new MyImage(imageItem.getName(), imageBlob);
HelpDebug.msg="after creating Image";
// persist image
BackendFactory.getInstance().SendImg(myImage);
HelpDebug.msg="after get instance ";
// respond to query
res.setContentType("text/plain");
res.getOutputStream().write("OK!".getBytes());
} catch (Exception ex)
{
try
{
res.getOutputStream().write(ex.getMessage().getBytes());
} catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
当我检查数据源查看器时,我可以看到创建了MyImage类型的对象 但没有合适的内容。 (名称字段为空)
我认为从jsp文件获取信息时遇到问题如下:
<%@page import="com.example.servlets.HelpDebug"%>
<%@ page language="java" contentType="text/html; charset=windows-1255"
pageEncoding="windows-1255"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type"
content="text/html; charset=windows-1255">
<title>Insert title here</title>
</head>
<body>
<form action="UploadImg" method="post" enctype="multipart/form-data">
<input name="name" type="text" value=""> <br /> <input
name="imageField" type="file" size="30"> <br /> <input
name="Submit" type="submit" value="Sumbit">
<%
HelpDebug.desc = request.getParameter("name") == null ? "null :P"
: request.getParameter("name");
out.println(HelpDebug.getMsg());
%>
</form>
</body>
</html>
servlet声明:
<servlet>
<servlet-name>UploadImg</servlet-name>
<servlet-class>com.example.servlets.UploadImg</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>UploadImg</servlet-name>
<url-pattern>/UploadImg</url-pattern>
</servlet-mapping>
任何想法??