我有如下所示的数据库表。
我要做的是获取colourschemes的所有记录，其中colour_1，colour_2，colour_3，colour_4，colour_5匹配任何用户＆＃39; agent_id的user_colour_1，user_colour_2或user_colour_3条目。
基本上，用户由代理注册，然后决定他们喜欢什么颜色。 colourschemes（商业用户）自行注册并指定他们所需的颜色。对于特定的代理人，我需要找到任何 colourschemes＆＃39;为他们选择的用户颜色的任何提供颜色。
----------------------
agents
----------------------
agent_id | agent_name
--------- | ----------
1 | Rod
2 | Jane
3 | Freddy
------------------------------------------------------------------------------
users
------------------------------------------------------------------------------
user_id | agent_id | user_name | user_colour_1 | user_colour_2 | user_colour_3
------- | -------- | --------- | ------------- | ------------- | -------------
1 | 1 | Andy | 1 | 2 | 3
2 | 2 | Betty | 2 | 1 | 5
3 | 3 | Claire | 3 | 1 | 6
4 | 1 | Derek | 4 | 5 | 7
5 | 1 | Eric | 1 | 6 | 2
6 | 2 | Fay | 2 | 7 | 3
7 | 3 | Gary | 3 | 1 | 7
------------------------------------------------------------------------------
----------------------------------------------------------------
colourschemes
----------------------------------------------------------------
scheme_id | colour_1 | colour_2 | colour_3 | colour_4 | colour_5
--------- | -------- | -------- | -------- | -------- | --------
1 | 1 | 2 | 3 | 5 | 7
2 | 2 | 3 | 5 | 1 | 4
3 | 3 | 6 | 7 | 2 | 4
4 | 4 | 3 | 1 | 7 | 2
5 | 5 | 6 | 7 | 2 | 3
6 | 6 | 5 | 1 | 4 | 3
7 | 7 | 3 | 6 | 1 | 2
-----------------------
colours
-----------------------
colour_id | colour_name
--------- | -----------
1 | red
2 | yellow
3 | blue
4 | green
5 | orange
6 | purple
7 | black
好的，抱歉这么长时间，但这里是想要的结果......
------------------------------------------
results table
------------------------------------------
agent_id | user_id | scheme_id | colour_id
------------------------------------------
1 | 1 | 1 | 1
1 | 1 | 1 | 2
1 | 1 | 1 | 3
1 | 1 | 2 | 2
1 | 1 | 2 | 1
1 | 1 | 2 | 3
1 | 1 | 3 | 3
1 | 1 | 3 | 2
1 | 1 | 4 | 3
1 | 1 | 4 | 1
1 | 1 | 4 | 2
1 | 1 | 5 | 2
1 | 1 | 5 | 3
1 | 1 | 6 | 1
1 | 1 | 6 | 3
1 | 1 | 7 | 3
1 | 1 | 7 | 1
1 | 1 | 7 | 2
1 | 4 | 1 | 5
1 | 4 | 1 | 7
1 | 4 | 2 | 5
1 | 4 | 2 | 4
1 | 4 | 3 | 7
1 | 4 | 3 | 4
1 | 4 | 4 | 4
1 | 4 | 4 | 7
1 | 4 | 5 | 5
1 | 4 | 5 | 4
1 | 4 | 6 | 5
1 | 4 | 6 | 4
1 | 4 | 7 | 7
1 | 5 | 1 | 1
1 | 5 | 1 | 2
1 | 5 | 2 | 2
1 | 5 | 2 | 1
1 | 5 | 3 | 6
1 | 5 | 3 | 2
1 | 5 | 4 | 6
1 | 5 | 4 | 2
1 | 5 | 5 | 6
1 | 5 | 5 | 1
1 | 5 | 6 | 1
1 | 5 | 6 | 2
1 | 5 | 7 | 6
1 | 5 | 7 | 1
1 | 5 | 7 | 2
答案 0 :(得分：0)
你要找的是一个像这样的复杂where子句。
SELECT
u.agent_id,
u.agent_name
from
users u,
colourschemes c
where
u.user_colour_1 = c.scheme_id
or u.user_colour_2 = c.scheme_id
or u.user_colour_3 = c.scheme_id
and c.colour_1 = "blue"
and c.colour_2 = "purple"
and c.colour_3 = "black"
and c.colour_4 = "yellow"
and c.colour_5 = "green" ;
答案 1 :(得分：0)
嗯，只是为了跟进，这是来自其他建议来源的建议代码......
SELECT u.user_id
, u.agent_id
, s.scheme_id
, u.user_colour_1 AS user_colour
FROM users u
INNER JOIN colourschemes ON (u.user_colour_1 = s.colour_1 OR u.user_colour_1 = s.colour_2 OR u.user_colour_1 = s.colour_3 OR u.user_colour_1 = s.colour_4 OR u.user_colour_1 = s.colour_5)
UNION ALL
SELECT u.user_id
, u.agent_id
, s.scheme_id
, u.user_colour_2 AS user_colour
FROM users u
INNER JOIN colourschemes ON (u.user_colour_2 = s.colour_1 OR u.user_colour_2 = s.colour_2 OR u.user_colour_2 = s.colour_3 OR u.user_colour_2 = s.colour_4 OR u.user_colour_2 = s.colour_5)
UNION ALL
SELECT u.user_id
, u.agent_id
, s.scheme_id
, u.user_colour_3 AS user_colour
FROM users u
INNER JOIN colourschemes ON (u.user_colour_3 = s.colour_1 OR u.user_colour_3 = s.colour_2 OR u.user_colour_3 = s.colour_3 OR u.user_colour_3 = s.colour_4 OR u.user_colour_3 = s.colour_5)