Question

该脚本没有任何问题，但我不想使用自定义对象

####################
# Get AD Site List # 
####################
Write-Verbose “Get AD Site List `r”
[array] $ADSites = [System.DirectoryServices.ActiveDirectory.Forest]::GetCurrentForest().Sites 
$ADSitesCount = $ADSites.Count
Write-Output “There are $ADSitesCount AD Sites `r”

ForEach ($Site in $ADSites)
    {  ## OPEN ForEach Site in ADSites
        $SiteName = $Site.Name
        $SiteSubnets = $Site.Subnets


        Write-Output “Site Name: $SiteName `r”
        Write-Output “Site Servers: $SiteServers `r”
        Write-Output ” `r”
    }

更新的脚本：

    #################### # Get AD Site List # #################### 
Write-Verbose “Get AD Site List r” 
$ADSites = [System.DirectoryServices.ActiveDirectory.Forest]::GetCurrentForest().Sites 
#$adsites= @{} 
$ADSitesCount = $ADSites.Count 
Write-Output “There are $ADSitesCount AD Sites r” 
$properties = @{'SiteName'=$ADSites.Name; 'SiteServers'=$ADSites.server; } 
$object = New-Object –TypeName PSObject –Prop $properties 
Write-Output $object

Answer 1

不确定你是否可能过度思考这个问题，但这只会使用Select-Object只获取你想要的属性，以表格格式提供相同的信息

$ADSites = [System.DirectoryServices.ActiveDirectory.Forest]::GetCurrentForest().Sites
Write-Output “There are $($ADSites.Count) AD Sites `r” 
$ADSites | Select-Object name,servers

混淆输出

There are 4 AD Sites 

Name                                               Servers                                          
----                                               -------                                          
SITE1                                              {SERVER1.DOMAIN.NET, SERVER2.DOMAIN.NET}           
STE345                                             {SERVER3.DOMAIN.NET}                               
LOCCOMP                                            {SERVER4.DOMAIN.NET}                                
THING                                              {SERVER9720.DOMAIN.NET, SERVER7.DOMAIN.NET}

Answer 2

问题出在这一行：

$properties = @{'SiteName'=$ADSites.Name; 'SiteServers'=$ADSites.server; }

$ ADSites是一个数组。它包含所有的网站名称，因此您将创建的内容如下所示：

Sites
----
{a, b, c}

解决方案是创建一个包含多个对象的数组，并为每个站点添加一个对象：

$collection= @()
foreach($site in $ADSites){
 $properties = @{ "Name" =$site.Name; "SiteServers"=$site.Server}
 $collection +=(New-Object –TypeName PSObject –Prop $properties )
}
$collection

写输出用于输出到管道而不是用于产生屏幕输出

添加自定义对象powershell

2 个答案: