Question

我有一个初始字符串，例如：

abab sbs abc ffuuu qwerty uii onnl ghj

我希望能够只提取不包含相邻重复字符的单词，以便上面的字符串返回为：

abc qwerty ghj

如何使用正则表达式完成此任务？

Answer 1

我想这个帖子在问题稍作修改后再次打开这将从评论移至答案区域。

不久前，我在一个关于没有重复字符的问题上看到了这种风格问题包含整个字符串。我刚把它翻译成单词边界。

@Michael J Mulligan为此做了一个测试案例（见评论）链接：
'工作正则表达式测试（regex101.com/r/bA2wB0/1）和一个有效的PHP示例（ideone.com/7ID8Ct）'

 # For NO duplicate letters anywhere within word characters
 # -----------------------------------------------------------
 # \b(?!\w*(\w)\w*\1)\w+

 \b               # Word boundry
                  # Only word chars now
 (?!              # Lookahead assertion (like a true/false conditional)
                       # It doesn't matter if the assertion is negative or positive.
                       # In this section, the engine is forced to match if it can,
                       # it has no choice, it can't backtrack its way out of here.
      \w* 
      ( \w )           # (1), Pick a word char, any word char
      \w* 
      \1               # Now it is here again
                       # Ok, the expression matched, time to check if the assertion is correct.
 )                # End assertion
 \w+              # Its here now, looks like the assertion let us through
                  # The assert is that no duplicate word chars ahead,
                  # so free to match word chars 'en masse'


 # For ONLY duplicate letters anywhere within word characters
 # just do the inverse. In this case, the inverse is changing 
 # the lookahead assertion to positive (want duplicates).
 # -----------------------------------------------------------
 # \b(?=\w*(\w)\w*\1)\w+

使用php regex查找没有重复字符的单词

1 个答案: