我有一个JSON对象,它由AJAX请求返回,但它一直返回undefined。
{
"shelters": [{
"id": 1,
"name": "ksk",
"introduce": "설정에서 변경해주세요",
"lonlat": "lon=14135650.08512,lat=4518305.530134",
"created_at": "2014-10-21T11:30:34.916Z",
"updated_at": "2014-10-21T12:16:24.943Z"
}, {
"id": 2,
"name": "aa",
"introduce": "설정에서 변경해주세요",
"lonlat": "lon=14135014.702323,lat=4518095.3283062",
"created_at": "2014-10-22T16:52:03.912Z",
"updated_at": "2014-10-22T16:53:07.407Z"
}]
}
alert(data.length);
alert(data.shelters.length);
alert(data.shelters);
为什么输出'未定义'?
答案 0 :(得分:0)
尝试这样的事情:
var myJson= JSON.parse('{"shelters":[{"id":1,"name":"ksk","introduce":"설정에서 변경해주세요","lonlat":"lon=14135650.08512,lat=4518305.530134","created_at":"2014-10-21T11:30:34.916Z","updated_at":"2014-10-21T12:16:24.943Z"},{"id":2,"name":"aa","introduce":"설정에서 변경해주세요","lonlat":"lon=14135014.702323,lat=4518095.3283062","created_at":"2014-10-22T16:52:03.912Z","updated_at":"2014-10-22T16:53:07.407Z"}]}');
console.log(myJson.shelters[0]);
答案 1 :(得分:0)
我认为您需要使用jQuery.getJSON()
代替jQuery.ajax()
。