Question

第一次预告

foreach (range(1, 70) as $num) {
   echo 'Number '.$num.'<br />';
}

第二

ksort($numbers);
foreach ($numbers as $key => $value){
    echo 'Number '.$key.' = '.$value.' times<br />';
}

First Foreach从1到70创建数字列表。 Second Foreach从db（ $ numbers ）中获取一些信息，如

Number 1 = 1 times
Number 2 = 1 times
Number 6 = 1 times
Number 11 = 1 times
Number 12 = 1 times
Number 13 = 1 times
Number 14 = 1 times
Number 16 = 1 times
Number 17 = 1 times
Number 21 = 2 times
Number 24 = 1 times
Number 25 = 1 times
Number 28 = 1 times
Number 30 = 1 times
Number 31 = 2 times
Number 33 = 1 times
Number 36 = 3 times
Number 38 = 1 times
Number 63 = 1 times
Number 65 = 1 times

现在我需要这样做：

if($key==$num){
echo 'Number '.$key.' = '.$value.' times<br />';
}else{
echo 'Number '.$key.' = 0 times<br />';
}

所有这些列表从1到70显示了多少次（如果存在）。感谢

Answer 1

我会为其创建一个关联数组，数字为键，值为数字。

$numbers = array();
foreach (range(1, 70) as $num)
{
   $numbers[$num] = 0;
}

并使用数据库循环将它们组合起来

foreach ($dbnumbers as $num => $value)
{
    $numbers[$num] += $value;
}

然后你可以迭代它来显示;）

Answer 2

对我来说，看起来你正在计算数字的出现次数。

$counter = array();
foreach ($numbers as $num) {
    if (!isset($counter[$num]) {
        $counter[$num] = 1;
    }
    else {
        $counter[$num]++;
    }
}

print_r($counter); # You have all of your occurrences loaded into this tidy array.

结合两个foreach php

2 个答案: