Android Nexus 7启用GPS传感器

时间:2014-10-22 14:52:05

标签: html5 gps

我刚刚开始使用HTML5和Phonegap进行一些应用开发。我正在尝试使用GPS - 禁用Wifi - 来显示lon / lat坐标。代码工作......有点像。

如果我打开应用程序,我找不到该位置。如果我打开任何其他使用地理定位的应用程序 - 谷歌地图或GPS测试仪 - 然后切换回我的应用程序,它会工作并更新坐标。这就像我的应用程序没有打开GPS传感器,但一旦它打开,我的应用程序可以访问它。

我错过了什么吗?

代码;

<script>
  window.onload = function() {
    var startPos;

    if (navigator.geolocation) {
      navigator.geolocation.getCurrentPosition(function(position) {
        enableHighAccuracy: true;
        startPos = position;
        document.getElementById("startLat").innerHTML = startPos.coords.latitude;
        document.getElementById("startLon").innerHTML = startPos.coords.longitude;
      }, function(error) {
        alert("Error occurred. Error code: " + error.code);
        // error.code can be:
        //   0: unknown error
        //   1: permission denied
        //   2: position unavailable (error response from locaton provider)
        //   3: timed out
      });

      navigator.geolocation.watchPosition(function(position) {
        enableHighAccuracy: true;
        document.getElementById("currentLat").innerHTML = position.coords.latitude;
        document.getElementById("currentLon").innerHTML = position.coords.longitude;
        document.getElementById("distance").innerHTML =
          calculateDistance(startPos.coords.latitude, startPos.coords.longitude,
                            position.coords.latitude, position.coords.longitude);
      });
    }
  };

  // Reused code - copyright Moveable Type Scripts - retrieved May 4, 2010.
  // http://www.movable-type.co.uk/scripts/latlong.html
  // Under Creative Commons License http://creativecommons.org/licenses/by/3.0/
  function calculateDistance(lat1, lon1, lat2, lon2) {
    var R = 6371; // km
    var dLat = (lat2-51.202399).toRad();
    var dLon = (lon2-parseFloat(-1.479645)).toRad();
    var a = Math.sin(dLat/2) * Math.sin(dLat/2) +
            Math.cos(51.202399.toRad()) * Math.cos(lat2.toRad()) *
            Math.sin(dLon/2) * Math.sin(dLon/2);
    var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
    var d = R * c;
    return d.toFixed(2);
  }
  Number.prototype.toRad = function() {
    return this * Math.PI / 180;
  }
</script>

祝你好运 安迪

1 个答案:

答案 0 :(得分:0)

使用org.apache.cordova.geolocation插件。

https://github.com/apache/cordova-plugin-geolocation