我目前正在处理客户端的导出视图，他们已经请求了一个带有附加列的数据透视表，后跟第一个数据透视表列，以便添加额外的详细信息。
我拥有的是：
SAMPLE_TAG SAMPLE_TYPE LAB_METHOD LAB_ELEMENT LAB_RESULT_NUMERIC
MCR0004140 OR ME-MS41 Ag 0.03
MCR0004140 OR ME-MS41 Au -0.2
MCR0004140 OR ME-MS41 Cu 15.3
MCR0004140 OR ME-MS41 Zn 19
MCR0005015 OR AG-OG46 Ag 421
MCR0005015 OR ME-MS41 Au -0.2
MCR0005015 OR ME-MS41 Cu 30.7
MCR0005015 OR ME-MS41 Zn 15
我想实现这个目标：
SAMPLE_TAG SAMPLE_TYPE Ag Ag_Method Au Au_Method Cu Cu_Method Zn Zn_Method
MCR0004140 OR 0.03 ME-MS41 -0.2 ME-MS41 15.3 ME-MS41 19 ME-MS41
MCR0005015 OR 421 AG-OG46 -0.2 ME-MS41 30.7 ME-MS41 15 ME-MS41
我可以使用以下内容获得第一个支点：
SELECT *
FROM TEMP_PIVOT
PIVOT (
MAX(LAB_RESULT_NUMERIC)
FOR LAB_ELEMENT IN ( [Au],[Ag],[Cu],[Zn],[Pt]) ) AS RESULT
然而，这是我被卡住的地方。
非常感谢任何帮助或建议。我在下面附加了创建表/插入脚本：
谢谢:)
CREATE TABLE [dbo].[TEMP_PIVOT](
[LAB_ID] [nvarchar](12) NOT NULL,
[DESPATCH_ID] [nvarchar](30) NULL,
[LAB_JOB_NO] [nvarchar](20) NULL,
[PROJECT] [nvarchar](16) NULL,
[SITE_ID] [nvarchar](16) NULL,
[SAMPLE_TAG] [nvarchar](16) NULL,
[SAMPLE_TYPE] [nvarchar](8) NULL,
[LAB_METHOD] [nvarchar](30) NOT NULL,
[LAB_ELEMENT] [nvarchar](8) NULL,
[LAB_RESULT_NUMERIC] [float] NULL) ON [PRIMARY]
INSERT [dbo].[TEMP_PIVOT] ([LAB_ID], [DESPATCH_ID], [LAB_JOB_NO], [PROJECT], [SITE_ID], [SAMPLE_TAG], [SAMPLE_TYPE], [LAB_METHOD], [LAB_ELEMENT], [LAB_RESULT_NUMERIC]) VALUES (N'ALS_MDZ', N'MIR00717', N'AN14036339', N'GORBEA', N'POINT_SAMPLE', N'MCR0004140', N'OR', N'ME-MS41', N'Ag', 0.03)
INSERT [dbo].[TEMP_PIVOT] ([LAB_ID], [DESPATCH_ID], [LAB_JOB_NO], [PROJECT], [SITE_ID], [SAMPLE_TAG], [SAMPLE_TYPE], [LAB_METHOD], [LAB_ELEMENT], [LAB_RESULT_NUMERIC]) VALUES (N'ALS_MDZ', N'MIR00717', N'AN14036339', N'GORBEA', N'POINT_SAMPLE', N'MCR0004140', N'OR', N'ME-MS41', N'Au', -0.2)
INSERT [dbo].[TEMP_PIVOT] ([LAB_ID], [DESPATCH_ID], [LAB_JOB_NO], [PROJECT], [SITE_ID], [SAMPLE_TAG], [SAMPLE_TYPE], [LAB_METHOD], [LAB_ELEMENT], [LAB_RESULT_NUMERIC]) VALUES (N'ALS_MDZ', N'MIR00717', N'AN14036339', N'GORBEA', N'POINT_SAMPLE', N'MCR0004140', N'OR', N'ME-MS41', N'Cu', 15.3)
INSERT [dbo].[TEMP_PIVOT] ([LAB_ID], [DESPATCH_ID], [LAB_JOB_NO], [PROJECT], [SITE_ID], [SAMPLE_TAG], [SAMPLE_TYPE], [LAB_METHOD], [LAB_ELEMENT], [LAB_RESULT_NUMERIC]) VALUES (N'ALS_MDZ', N'MIR00717', N'AN14036339', N'GORBEA', N'POINT_SAMPLE', N'MCR0004140', N'OR', N'ME-MS41', N'Zn', 19)
INSERT [dbo].[TEMP_PIVOT] ([LAB_ID], [DESPATCH_ID], [LAB_JOB_NO], [PROJECT], [SITE_ID], [SAMPLE_TAG], [SAMPLE_TYPE], [LAB_METHOD], [LAB_ELEMENT], [LAB_RESULT_NUMERIC]) VALUES (N'ALS_MDZ', N'MIR00717', N'AN14036339', N'GORBEA', N'POINT_SAMPLE', N'MCR0005015', N'OR', N'AG-OG46', N'Ag', 421)
INSERT [dbo].[TEMP_PIVOT] ([LAB_ID], [DESPATCH_ID], [LAB_JOB_NO], [PROJECT], [SITE_ID], [SAMPLE_TAG], [SAMPLE_TYPE], [LAB_METHOD], [LAB_ELEMENT], [LAB_RESULT_NUMERIC]) VALUES (N'ALS_MDZ', N'MIR00717', N'AN14036339', N'GORBEA', N'POINT_SAMPLE', N'MCR0005015', N'OR', N'ME-MS41', N'Au', -0.2)
INSERT [dbo].[TEMP_PIVOT] ([LAB_ID], [DESPATCH_ID], [LAB_JOB_NO], [PROJECT], [SITE_ID], [SAMPLE_TAG], [SAMPLE_TYPE], [LAB_METHOD], [LAB_ELEMENT], [LAB_RESULT_NUMERIC]) VALUES (N'ALS_MDZ', N'MIR00717', N'AN14036339', N'GORBEA', N'POINT_SAMPLE', N'MCR0005015', N'OR', N'ME-MS41', N'Cu', 30.7)
INSERT [dbo].[TEMP_PIVOT] ([LAB_ID], [DESPATCH_ID], [LAB_JOB_NO], [PROJECT], [SITE_ID], [SAMPLE_TAG], [SAMPLE_TYPE], [LAB_METHOD], [LAB_ELEMENT], [LAB_RESULT_NUMERIC]) VALUES (N'ALS_MDZ', N'MIR00717', N'AN14036339', N'GORBEA', N'POINT_SAMPLE', N'MCR0005015', N'OR', N'ME-MS41', N'Zn', 15)
答案 0 :(得分：0)
仅供参考（如果你不关心解决方案是否不是关于支点，而是为了解决业务问题的结果），这里是一个快速替代和简单的方法。 / p>
SELECT
SAMPLE_TAG,
SAMPLE_TYPE,
MAX(CASE WHEN LAB_ELEMENT = 'Ag' THEN LAB_RESULT_NUMERIC ELSE NULL END) AS [Ag],
MAX(CASE WHEN LAB_ELEMENT = 'Ag' THEN LAB_METHOD ELSE NULL END) AS [Ag_Method],
MAX(CASE WHEN LAB_ELEMENT = 'Au' THEN LAB_RESULT_NUMERIC ELSE NULL END) AS [Au],
MAX(CASE WHEN LAB_ELEMENT = 'Au' THEN LAB_METHOD ELSE NULL END) AS [Au_Method],
MAX(CASE WHEN LAB_ELEMENT = 'Cu' THEN LAB_RESULT_NUMERIC ELSE NULL END) AS [Cu],
MAX(CASE WHEN LAB_ELEMENT = 'Cu' THEN LAB_METHOD ELSE NULL END) AS [Cu_Method],
MAX(CASE WHEN LAB_ELEMENT = 'Zn' THEN LAB_RESULT_NUMERIC ELSE NULL END) AS [Zn],
MAX(CASE WHEN LAB_ELEMENT = 'Zn' THEN LAB_METHOD ELSE NULL END) AS [Zn_Method],
MAX(CASE WHEN LAB_ELEMENT = 'Pt' THEN LAB_RESULT_NUMERIC ELSE NULL END) AS [Pt],
MAX(CASE WHEN LAB_ELEMENT = 'Pt' THEN LAB_METHOD ELSE NULL END) AS [Pt_Method]
FROM dbo.TEMP_PIVOT
GROUP BY
SAMPLE_TAG,
SAMPLE_TYPE
输出
SAMPLE_TAG SAMPLE_TYPE Ag Ag_Method Au Au_Method Cu Cu_Method Zn Zn_Method Pt Pt_Method
---------------- ----------- ---------------------- ------------------------------ ---------------------- ------------------------------ ---------------------- ------------------------------ ---------------------- ------------------------------ ---------------------- ------------------------------
MCR0004140 OR 0.03 ME-MS41 -0.2 ME-MS41 15.3 ME-MS41 19 ME-MS41 NULL NULL
MCR0005015 OR 421 AG-OG46 -0.2 ME-MS41 30.7 ME-MS41 15 ME-MS41 NULL NULL
答案 1 :(得分：0)
这是带有多个支点的版本
;WITH E AS (
SELECT
SAMPLE_TAG,
SAMPLE_TYPE,
LAB_ELEMENT AS E1,
LAB_ELEMENT + '_Method' AS E2,
LAB_RESULT_NUMERIC,
LAB_METHOD
FROM dbo.TEMP_PIVOT
)
SELECT
SAMPLE_TAG,
SAMPLE_TYPE,
MAX([Ag]) AS [Ag],
MAX([Ag_Method]) AS [Ag_Method],
MAX([Au]) AS [Au],
MAX([Au_Method]) AS [Au_Method],
MAX([Cu]) AS [Cu],
MAX([Cu_Method]) AS [Cu_Method],
MAX([Zn]) AS [Zn],
MAX([Zn_Method]) AS [Zn_Method],
MAX([Pt]) AS [Pt],
MAX([Pt_Method]) AS [Pt_Method]
FROM E
PIVOT ( MAX(LAB_RESULT_NUMERIC) FOR E1 IN ( [Au],[Ag],[Cu],[Zn],[Pt]) ) AS R1
PIVOT ( MAX(LAB_METHOD) FOR E2 IN ( [Au_Method],[Ag_Method],[Cu_Method],[Zn_Method],[Pt_Method]) ) AS R2
GROUP BY
SAMPLE_TAG,
SAMPLE_TYPE
ORDER BY
SAMPLE_TAG,
S
输出相同
SAMPLE_TAG SAMPLE_TYPE Ag Ag_Method Au Au_Method Cu Cu_Method Zn Zn_Method Pt Pt_Method
---------------- ----------- ---------------------- ------------------------------ ---------------------- ------------------------------ ---------------------- ------------------------------ ---------------------- ------------------------------ ---------------------- ------------------------------
MCR0004140 OR 0.03 ME-MS41 -0.2 ME-MS41 15.3 ME-MS41 19 ME-MS41 NULL NULL
MCR0005015 OR 421 AG-OG46 -0.2 ME-MS41 30.7 ME-MS41 15 ME-MS41 NULL NULL
答案 2 :(得分：0)
如果您希望查询动态运行，请尝试使用
DECLARE @L_ELEMENT VARCHAR(max)='',
@aggL_ELEMENTMTD VARCHAR(max)='',
@L_ELEMENTMTD VARCHAR(max)='',
@aggL_ELEMENT VARCHAR(max)='',
@sql NVARCHAR(max)
SET @L_ELEMENT = (SELECT DISTINCT Quotename(lab_element) + ','
FROM temp_pivot
FOR xml path(''))
SET @aggL_ELEMENTMTD = (SELECT DISTINCT ' max('
+ Quotename(lab_element+'_Method') +
') '
+ Quotename(lab_element+'_Method') + ','
FROM temp_pivot
FOR xml path(''))
SET @L_ELEMENTMTD = (SELECT DISTINCT Quotename(lab_element+'_Method') + ','
FROM temp_pivot
FOR xml path(''))
SET @aggL_ELEMENT = (SELECT DISTINCT ' max(' + Quotename(lab_element) + ') '
+ Quotename(lab_element) + ','
FROM temp_pivot
FOR xml path(''))
SELECT @L_ELEMENTMTD = LEFT(@L_ELEMENTMTD, Len(@L_ELEMENTMTD) - 1)
SELECT @L_ELEMENT = LEFT(@L_ELEMENT, Len(@L_ELEMENT) - 1)
SELECT @aggL_ELEMENT = LEFT(@aggL_ELEMENT, Len(@aggL_ELEMENT) - 1)
SELECT @aggL_ELEMENTMTD = LEFT(@aggL_ELEMENTMTD, Len(@aggL_ELEMENTMTD) - 1)
SET @sql = 'SELECT SAMPLE_TAG,SAMPLE_TYPE,' + @aggL_ELEMENT + ','
+ @aggL_ELEMENTMTD + ' FROM (select LAB_ELEMENT+''_Method'' L_ELEMENTMTD,*
FROM TEMP_PIVOT) AS T
PIVOT (max(LAB_RESULT_NUMERIC) FOR LAB_ELEMENT
IN (' + @L_ELEMENT + ')) AS P1
PIVOT (max(LAB_METHOD) FOR L_ELEMENTMTD
IN (' + @L_ELEMENTMTD + ')) AS P1
group by SAMPLE_TAG, SAMPLE_TYPE'
--PRINT @sql
EXEC Sp_executesql
@sql