我需要帮助获取List<WebElement>
的xpath以及如何遍历它并选择等于&#34; 2014的好处&#34;的链接文本。来自以下代码。
<tbody id="tblPriorEventsBody">
<tr>
<td>01/01/2014</td>
<td>
<a class="openEvent aActive" onclick='DisplayEventYearElections("dvCurrentElections","2014","Benefits For 01/01/2014 Open Enrollment ( 2014 ) ","2e82be0c-f280-4502-9d98-cf995450442c");' href="#">
2014 Benefits
</a>
<input id="hfOpenEventDefinationId" type="hidden" value="b991cf84-f197-413f-a3fb-21c5a1c0d70a"></input>
</td>
<td>N/A</td>
<td>N/A</td>
</tr>
<tr>...</tr> // Each tr contains a link
<tr>...</tr>
<tr>...</tr>
<tr>...</tr>
<tr>...</tr>
</tbody>
我正在尝试使用以下代码:
List <WebElement> options = Driver.findElements(By.xpath("//tbody[@id='tblOpenEventsBody']//tr/a"));
System.out.println(" CLASS Elements size " + options.size());
for (WebElement option : options) {
String Str = "2014 Benefits" // based on string text match I want to select
if("Str".equals(option.getText())){
option.click();
break();
}
答案 0 :(得分:4)
你可以做点像......
List<WebElement> links = driver.find elements(By.cssSelector('#tblPriorEventsBody td a'));
Iterator<WebElement> iter = links.iterator();
while(iter.hasNext()) {
WebElement we = iter.next();
if (we.text.equals("whatever") {
we.click;
// do something in else perhaps
}
}
答案 1 :(得分:3)
通过链接文本查找链接将更加可靠,可读和明确:
WebElement element = Driver.findElement(By.linkText("2014 Benefits"));