Question

我是谷歌测试和谷歌模拟的新手，所以我仍然有点困惑。我只是尝试使用整数加法，乘法和除法来实现一个简单的计算器，并为它创建一个遵循真实行为的模拟。我该如何解决或在哪里做错了？

还可以向我解释，我如何确定它是在嘲笑原始类而不是直接调用原始类？谢谢你。

这是CBasicMath.hpp：

#ifndef BASIC_MATH_HPP__
#define BASIC_MATH_HPP__

class CBasicMath
{
public:
    CBasicMath(){}
    virtual ~CBasicMath() {}
    virtual int Addition(int x, int y);
    virtual int Multiply(int x, int y);
    virtual int Divide(int x, int y);
};

#endif //BASIC_MATH_HPP__

这是CBasicMath.cpp：

#include "CBasicMath.hpp"

int CBasicMath::Addition(int x, int y)
{
   return (x + y);
}

int CBasicMath::Multiply(int x, int y)
{
   return (x * y);
}

int CBasicMath::Divide(int x, int y)
{
   return (x / y);
}

这是mock_basic_test.cpp：

#include "gmock/gmock.h"
#include "CBasicMath.cpp"

using ::testing::_;
using ::testing::AtLeast;
using ::testing::Invoke;

class MockBasicTest : public CBasicMath {
public:
    MockBasicTest() {
    // By default, all calls are delegated to the real object.
    ON_CALL(*this, Addition(_))
        .WillByDefault(Invoke(&real_, &CBasicMath::Addition));
    ON_CALL(*this, Multiply(_))
        .WillByDefault(Invoke(&real_, &CBasicMath::Multiply));
    ON_CALL(*this, Divide(_))
        .WillByDefault(Invoke(&real_, &CBasicMath::Divide));
  }
    MOCK_METHOD2(Addition, int(int x, int y));
    MOCK_METHOD2(Multiply, int(int x, int y));
    MOCK_METHOD2(Divide, int(int x, int y));
private:
    CBasicMath real_;
};

这是TestBasicMath：

#include "mock_basic_test.h"
#include "gtest/gtest.h"
#include "gmock/gmock.h"

class BasicMathTest : public ::testing::Test {
protected:
    BasicMathTest() {}

    virtual ~BasicMathTest() {}

    virtual void SetUp() {
        mTestObj = new CBasicMath();
    }

    virtual void TearDown() {
        delete mTestObj;
    }
    CBasicMath *mTestObj;
};

TEST_F(BasicMathTest, testAddition) {
    MockBasicTest basictest;
    EXPECT_CALL(basictest, Addition(2,3))
        .Times(1);
    EXPECT_EQ(5,basictest.Addition(2,3));
}

TEST_F(BasicMathTest, testMultiply) {
    EXPECT_EQ(6,mTestObj->Multiply(2,3));
}

TEST_F(BasicMathTest, testDivide) {
    EXPECT_EQ(6,mTestObj->Divide(6,1));
}

int main(int argc, char **argv) {
    ::testing::InitGoogleTest(&argc, argv);
    return RUN_ALL_TESTS();
}

它为我提供了以下所有三个函数的错误：

In file included from /home/gmock-1.7.0/include/gmock/gmock-generated-function-mockers.h:43:0,
                 from /home/gmock-1.7.0/include/gmock/gmock.h:61,
                 from mock_basic_test.h:1,
                 from TestBasicMath_GoogleTest.cpp:1:
mock_basic_test.h: In constructor ‘MockBasicTest::MockBasicTest()’:
mock_basic_test.h:12:30: error: no matching function for call to ‘MockBasicTest::gmock_Addition(const testing::internal::AnythingMatcher&)’
     ON_CALL(*this, Addition(_))
                             ^
mock_basic_test.h:12:30: note: candidate is:
In file included from /home/gmock-1.7.0/include/gmock/gmock.h:61:0,
                 from mock_basic_test.h:1,
                 from TestBasicMath_GoogleTest.cpp:1:
mock_basic_test.h:19:2: note: testing::internal::MockSpec<int(int, int)>&MockBasicTest::gmock_Addition(const testing::Matcher<int>&, const testing::Matcher<int>&)
  MOCK_METHOD2(Addition, int(int x, int y));
  ^
mock_basic_test.h:19:2: note:   candidate expects 2 arguments, 1 provided

再次感谢您的帮助。

Answer 1

在模拟类构造函数代码中

ON_CALL(*this, Addition(_))
    .WillByDefault(Invoke(&real_, &CBasicMath::Addition));

匹配器的数量（_）需要与为函数签名定义的参数数量相同：

ON_CALL(*this, Addition(_,_))
                    //   ^^  Add an additional matcher
    .WillByDefault(Invoke(&real_, &CBasicMath::Addition));

// ...

MOCK_METHOD2(Addition, int(int x, int y));
                        // ^^^^^  ^^^^^ here you have 2 parameters need matching

Answer 2

仅当“T real_”可以默认构造时才有效。此外，您还可以在模拟中获得另一个T副本，这是不需要的。

Imho你可以这样做，因为你正在访问基类：

ON_CALL(*this, Addition(_))
    .WillByDefault(Invoke(*this, &CBasicMath::Addition));

这种方式只是将调用分配给基类。

谷歌模拟测试一个类的真实行为

2 个答案: