Question

我试图在向量中找到一个枚举项，好像有些==运算符问题。请问任何指导？

这是枚举

enum RESPONSE{
 GAME_START='P',
 GAME_HELP='H',
 GAME_QUIT='Q'
}

以下是用法

std::string s = getinputChar(); //this returns a string with a one character.

std::vector<RESPONSE> responces;
responces.push_back(GAME_START);
responces.push_back(GAME_QUIT);

std::vector<RESPONSE>::iterator it = find (responces.begin(), responces.end(), s.c_str());

错误：

error C2678: binary '==' : no operator found which takes a left-hand operand of type 'RESPONSE' (or there is no acceptable conversion)

Answer 1

您可以接受他们的输入char而不是string

char s = getinputChar();

然后，您可以将find更改为

std::vector<RESPONSE>::iterator it = find (responces.begin(), responces.end(), static_cast<RESPONSE>(s));

Answer 2

试试这个：

RESPONSE r = (RESPONSE) s[0]; // conversion from input string to RESPONSE
std::vector<RESPONSE>::iterator it = find (responces.begin(), responces.end(), r);

Answer 3

c_str()会返回const char *，但您的向量包含枚举。你想比较第一个角色吗？试试find(responces.begin(), responces.end(), static_cast<RESPONSE>(s[0]))。如果添加值大于char

的枚举，则此操作将停止

在枚举向量中找到

3 个答案: