Question

static void Main(string[] args)
{
    //read in the file
    StreamReader convert = new StreamReader("../../convert.txt");

    //define variables
    string line = convert.ReadLine();
    int conversion;
    int numberIn;
    float conversionFactor;

    Console.WriteLine("Enter the conversion in the form (amount,from,to)");
    String inputMeasurement = Console.ReadLine();
    string[] inputMeasurementArray = inputMeasurement.Split(',');

    while (line != null)
    {
        string[] fileMeasurementArray = line.Split(',');
        if (fileMeasurementArray[0] == inputMeasurementArray[1])
        {
            if (fileMeasurementArray[1] == inputMeasurementArray[2])
            {
                Console.WriteLine("{0}", fileMeasurementArray[2]);
            }
        }

        line = convert.ReadLine();

        //convert to int
        numberIn = Convert.ToInt32(inputMeasurementArray[0]);
        conversionFactor = Convert.ToInt32(fileMeasurementArray[2]);

        conversion = (numberIn * conversionFactor);
    }

    Console.ReadKey();
}

在conversionFactor = Convert.ToInt32(fileMeasurementArray[2]);行上，我收到错误消息“输入字符串格式不正确”。请帮忙！

文本文件包含以下内容：

ounce,gram,28.0
pound,ounce,16.0
pound,kilogram,0.454
pint,litre,0.568
inch,centimetre,2.5
mile,inch,63360.0

Answer 1

根据文本文件的行，fileMeasurementArray[2]将为28.0 pound。这不能转换为int。您应该删除字符串并仅保留数字28.0。

更新：问题已更新，文本文件行已更正。所以我以前的回答再也没有意义了。

问题可能是因为您尝试将float转换为int。

Answer 2

您正在尝试将float转换为int。

将conversionFactor定义为double

变量转换也需要是双倍的。

喜欢这样

using System;
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.IO;

namespace measurementConverter { 
    class Program 
    { 
        static void Main(string[] args) 
        {  //read in the file 
            StreamReader convert = new StreamReader("../../convert.txt");

            //define variables
            string line = convert.ReadLine();
            double conversion;
            int numberIn;
            double conversionFactor;

            Console.WriteLine("Enter the conversion in the form (amount,from,to)");
            String inputMeasurement = Console.ReadLine();
            string[] inputMeasurementArray = inputMeasurement.Split(',');

            while (line != null)
            {
                string[] fileMeasurementArray = line.Split(',');
                if (fileMeasurementArray[0] == inputMeasurementArray[1])
                {
                    if (fileMeasurementArray[1] == inputMeasurementArray[2])
                    {
                        Console.WriteLine("{0}", fileMeasurementArray[2]);
                    }
                }

                line = convert.ReadLine();

                //convert to int
                numberIn = Convert.ToInt32(inputMeasurementArray[0]);
                conversionFactor = Convert.ToDouble(fileMeasurementArray[2]);

                conversion = (numberIn * conversionFactor);
            }



            Console.ReadKey();


        }
    }
}

Answer 3

'28 .0 pound'不是整数。我想这就是你的问题所在。

Answer 4

numberIn和conversionFactor是花车，而不是Ints。使用：

float numberIn;
float conversionFactor;
...

//convert to float
numberIn = Convert.ToSingle(inputMeasurementArray[0]);
conversionFactor = Convert.ToSingle(fileMeasurementArray[2]);

输入字符串的格式不正确

4 个答案: