我正在开发一个项目，其中我需要不同的任务以获得不同的时间，就像用户在5毫秒之后按钮然后执行代码并且如果按下时间更多那么那么不同
实际上是在Facebook聊天中创建一个聊天室
问题是关于ActionDown事件，我想打开或启动我的应用程序
但问题是当用户尝试将聊天头从一个位置重新分配给其他事件时 喜欢
This is my code
这里在ACTION_DOWN事件中我想要对应用程序
public class ChadHead extends Service {
private final Handler mHandler = new Handler();
private Runnable mTimer1;
private WindowManager windowManager;
private ImageView chatHead;
Display display;
int width;
int count=0;
@Override
public IBinder onBind(Intent intent) {
// Not used
return null;
}
@Override
public void onCreate() {
super.onCreate();
mTimer1 = new Runnable() {
@Override
public void run() {
count++;
// TODO Auto-generated method stub
mHandler.postDelayed(this, 5000);
if (count == 1) {
mHandler.removeCallbacks(mTimer1);
// put your code here:
}
}
};
windowManager = (WindowManager) getSystemService(WINDOW_SERVICE);
chatHead = new ImageView(this);
chatHead.setImageResource(R.drawable.ic_launcher);
final WindowManager.LayoutParams params = new WindowManager.LayoutParams(
WindowManager.LayoutParams.WRAP_CONTENT,
WindowManager.LayoutParams.WRAP_CONTENT,
WindowManager.LayoutParams.TYPE_PHONE,
WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE,
PixelFormat.TRANSLUCENT);
params.gravity = Gravity.TOP | Gravity.LEFT;
params.x = 0;
params.y = 100;
windowManager.addView(chatHead, params);
chatHead.setOnTouchListener(new View.OnTouchListener() {
private int initialX;
private int initialY;
private float initialTouchX;
private float initialTouchY;
@SuppressWarnings("deprecation")
@Override
public boolean onTouch(View v, MotionEvent event) {
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
initialX = params.x;
initialY = params.y;
initialTouchX = event.getRawX();
initialTouchY = event.getRawY();
mHandler.postDelayed(mTimer1, 0);
/*Intent i;
PackageManager manager = getPackageManager();
try {
i = manager.getLaunchIntentForPackage("com.technorapper.technorappermapp");
if (i == null)
throw new PackageManager.NameNotFoundException();
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
} catch (PackageManager.NameNotFoundException e) {
}*/
Toast.makeText(getApplicationContext(), "TechnoRapper", 50)
.show();
return true;
case MotionEvent.ACTION_MOVE:
params.x = initialX
+ (int) (event.getRawX() - initialTouchX);
params.y = initialY
+ (int) (event.getRawY() - initialTouchY);
windowManager.updateViewLayout(chatHead, params);
display = windowManager.getDefaultDisplay();
width = display.getWidth();
return true;
case MotionEvent.ACTION_UP:
count = 0;
if (initialTouchX < width / 2) {
initialTouchX = 0;
} else if (initialTouchX >= width / 2) {
initialTouchX = width;
}
return true;
}
return false;
}
});
}
@Override
public void onDestroy() {
super.onDestroy();
if (chatHead != null)
windowManager.removeView(chatHead);
}
}
答案 0 :(得分：2)
您可以使用View.OnTouchListener和两个时间戳来存储按钮单击开始（ACTION_DOWN）和结束时间（ACTION_UP）。然后，这2个变量（end-start）之间的差异将告诉您按钮点击时间的持续时间，您可以根据自己的喜好执行代码。
test.setOnTouchListener(new OnTouchListener() {
private long start = 0;
private long end = 0;
@Override
public boolean onTouch(View v, MotionEvent event) {
if (event.getAction()==MotionEvent.ACTION_DOWN) {
this.start = System.currentTimeMillis();
} else if (event.getaction()==MotionEvent.ACTION_UP) {
this.end = System.currentTimeMillis();
}
}
});
答案 1 :(得分：2)
我在3个月前面对它，这是我的解决方案：
private int count = 0;
Button btn;
private final Handler mHandler = new Handler();
private Runnable mTimer1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
btn = (Button) findViewById(R.id.btn);
mTimer1 = new Runnable() {
@Override
public void run() {
count++;
// TODO Auto-generated method stub
mHandler.postDelayed(this, 500);
if (count == 1) {
mHandler.removeCallbacks(mTimer1);
// put your code here:
Intent i;
PackageManager manager = getPackageManager();
try {
i = manager.getLaunchIntentForPackage("com.technorapper.technorappermapp");
if (i == null)
throw new PackageManager.NameNotFoundException();
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
} catch (PackageManager.NameNotFoundException e) {
}
}
}
};
btn.setOnTouchListener(new OnTouchListener() {
private int initialX;
private int initialY;
private float initialTouchX;
private float initialTouchY;
@Override
public boolean onTouch(View v, final MotionEvent event) {
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
initialX = (int) btn.getX();
initialY = (int) btn.getY();
initialTouchX = event.getRawX();
initialTouchY = event.getRawY();
mHandler.postDelayed(mTimer1, 0);
return true;
case MotionEvent.ACTION_UP:
count = 0;
return true;
case MotionEvent.ACTION_MOVE:
runOnUiThread(new Runnable() {
public void run() {
btn.setX(initialX
+ (int) (event.getRawX() - initialTouchX));
btn.setY(initialY
+ (int) (event.getRawY() - initialTouchY));
}
});
return true;
}
return false;
}
});
使用此代码，您可以移动聊天头，并在500毫秒后启动事件。无需使用OnClickListener，检查位置是否未更改，因此将其检测为OnClickListener 如果你想在捕获一些动作时停止OnTouch事件，只需在ACTION_MOVE中放入'boolean variable'
答案 2 :(得分：1)
如果你想要自定义持续时间，你必须自己编程。
但是建议在函数中使用android build。 有一个View.OnLongClickListener和一个View.OnClickListener可以区分两个不同的持续时间来点击视图。
答案 3 :(得分：0)
我无法告诉你完整的确切代码但是我可以解释这里的流程，我从你的答案得到的是你需要在上次按下按钮时做不同的动作，这是你怎么做您需要两个Date变量，即current和lastTime
DateTimeUtils.getCurrentUTCFormattedDateTime()
将lastTime存储在首选项的操作中，从首选项中获取最后一次并获取当前时间并减去它，以获得差异。
long difference = (current.getTime() - lastSaved.getTime()) / 1000;
以秒为单位给你时差，然后你决定做什么。希望它有所帮助：）