Question

import play.api.libs.json._
import scala.util.parsing.json.{JSON, JSONArray, JSONObject}

我有以下json数组 -

 val groupNameList = Json.arr(
    Json.obj(
      "groupName" -> "All",
      "maxSeverity" -> allGroupSeverityCount,
      "hostCount" -> (windowsCount + linuxCount + esxCount + networkCount + storageCount + awsLinuxCount + awsWindowsCount)),
    Json.obj(
      "groupName" -> "Private",
      "maxSeverity" -> privateGroupSeverityCount,
      "hostCount" -> (windowsCount + linuxCount + esxCount + networkCount + storageCount)),
    Json.obj(
      "groupName" -> "Public",
      "maxSeverity" -> publicGroupSeverityCount,
      "hostCount" -> (awsLinuxCount + awsWindowsCount))
   )

我想将以下json对象列表附加到此数组 -

List({"groupName" : "group1", "maxSeverity" : 10, "hostCount" : 1, "members" : ["192.168.20.30", "192.168.20.31", "192.168.20.53", "192.168.20.50"]})

我想将列表合并到数组中。

如何使用scala ???

将给定列表附加到json数组

Answer 1

在不同JSON库类型之间转换对象的最简单（尽管可能不是最有效）方法是通过其JSON字符串表示。

(o: JSONObject => Json.parse(o.toString()))

获得List[JsObject]后，您可以将其传递到JsArray构造函数，然后使用++连接两个JsArray。

将它放在一个例子中：

import play.api.libs.json.{Json, JsArray}
import scala.util.parsing.json.JSONObject

object Foo {

  val jsArray = Json.arr(
    Json.obj("a" -> "b", "c" -> 2),
    Json.obj("d" -> "e", "f" -> 3))

  val list = List(
    JSONObject(Map("g" -> "h", "i" -> 4)),
    JSONObject(Map("j" -> "k", "m" -> 5))
  )

  def main(args: Array[String]): Unit = {
    println(jsArray ++ JsArray(list.map(o => Json.parse(o.toString()))))
    // [{"a":"b","c":2},{"d":"e","f":3},{"g":"h","i":4},{"j":"k","m":5}]
  }
}

如何将Play JSON对象与parser-combinator JSONObjects结合起来？

1 个答案: