我有一个关于这个HiLo游戏的快速问题,我一直试图解决这个问题。当我运行程序时,它计算0-10范围之外的猜测,但我不希望它这样做。我该如何解决这个问题?这是我的代码。
import java.util.Random; // Random number generator class
import java.util.Scanner; // reads user inputs
public class HiLo
{
public static void main(String[] args)
{
// declare variables
final int MAX = 10;
int answer, guess;
int numberOfTries = 0;
String again;
Scanner Keyboard = new Scanner(System.in);
do
{
System.out.print(" I'm thinking of a number between 0 and "
+ MAX + ". Guess what it is: ");
guess = Keyboard.nextInt();
// guess
Random generator = new Random(); // Random number generator. 0 to 10.
answer = generator.nextInt(MAX) + 1;
if (guess > 10) // if guess is bigger than 10 then error message
{
System.out.println("ERROR – Your guess is out of the range 0 to 10.");
}
if (guess < 0) // if guess is smaller than 0 then error message
{
System.out.println("ERROR – Your guess is out of the range 0 to 10.");
}
while (guess != answer) // If guess is not the answer
{
if (guess > answer) // If guess is more than the answer
{
System.out.println("You guessed too high! \nTry again:");
guess = Keyboard.nextInt();
}
if (guess < answer)// If guess is less than the answer
{
System.out.println("Too Low! \nTry again:");
guess = Keyboard.nextInt();
}
numberOfTries = numberOfTries + 1;
}// end of the loop
// display result
if (guess == answer)
{
numberOfTries += 1;
System.out.println("YOU WIN!");
System.out.println("It took you " + numberOfTries + " tries!");
System.out.println();
System.out.print("Do you want to play again(Y/N)?");
}
Keyboard.nextLine(); // skip over enter key
again = Keyboard.nextLine();
numberOfTries = 0;
} while (again.equalsIgnoreCase("Y"));
} // end of class
} // end of main
答案 0 :(得分:0)
您报告错误但不要continue;
(并使用逻辑||
)
if (guess < 0 || guess > 10) {
System.out.println ("ERROR – Your guess is out of the range 0 to 10.");
again = "Y"; // <-- make sure we'll re-evaluate.
continue; // <-- Add then skip the rest of the loop body
}