Question

我需要一个可以将新的xml子节点插入/附加到预先存在的xml父节点的脚本。

--New child nodes
DECLARE @XMLChildData XML
SET @XMLChildData = '
<Persons>
    <Person>
        <Firstname>Gary</Firstname>
        <Surname>Smith</Surname>
        <Telephone>0115547899</Telephone>
        <Address>
            <AddressLine>1 Church Lane</AddressLine>
            <AddressLine>Rosebank</AddressLine>
            <AddressLine>Houghton</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Wayne</Firstname>
        <Surname>Farmey</Surname>
        <Telephone>0117453269</Telephone>
        <Address>
            <AddressLine>51 Oak Street</AddressLine>
            <AddressLine>Rivionia</AddressLine>
            <AddressLine>Sandton</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Mark</Firstname>
        <Surname>Jones</Surname>
        <Telephone>0119854741</Telephone>
        <Address>
            <AddressLine>4 Arum Lane</AddressLine>
            <AddressLine>Glen Hazel</AddressLine>
            <AddressLine>Johannesburg</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
</Persons>'

--Existing parent node
DECLARE @XMLParentData XML
SET @XMLParentData = '
<Persons>
    <Person>
        <Firstname>Sarah</Firstname>
        <Surname>Gray</Surname>
        <Telephone>0113265874</Telephone>
        <Address>
            <AddressLine>78 Emerl Aveune</AddressLine>
            <AddressLine>Fourways</AddressLine>
            <AddressLine>Sandton</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Jenna</Firstname>
        <Surname>Reed</Surname>
        <Telephone>0114781102</Telephone>
        <Address>
            <AddressLine>6 Park Lane</AddressLine>
            <AddressLine>Parkhurst</AddressLine>
            <AddressLine>Rosebank</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Mike</Firstname>
        <Surname>Wilke</Surname>
        <Telephone>0116532003</Telephone>
        <Address>
            <AddressLine>22 High Road</AddressLine>
            <AddressLine>Modderfontein</AddressLine>
            <AddressLine>Edenvale</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
</Persons>'

我希望最终结果是：

<Persons>
    <Person>
        <Firstname>Sarah</Firstname>
        <Surname>Gray</Surname>
        <Telephone>0113265874</Telephone>
        <Address>
            <AddressLine>78 Emerl Aveune</AddressLine>
            <AddressLine>Fourways</AddressLine>
            <AddressLine>Sandton</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Jenna</Firstname>
        <Surname>Reed</Surname>
        <Telephone>0114781102</Telephone>
        <Address>
            <AddressLine>6 Park Lane</AddressLine>
            <AddressLine>Parkhurst</AddressLine>
            <AddressLine>Rosebank</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Mike</Firstname>
        <Surname>Wilke</Surname>
        <Telephone>0116532003</Telephone>
        <Address>
            <AddressLine>22 High Road</AddressLine>
            <AddressLine>Modderfontein</AddressLine>
            <AddressLine>Edenvale</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Gary</Firstname>
        <Surname>Smith</Surname>
        <Telephone>0115547899</Telephone>
        <Address>
            <AddressLine>1 Church Lane</AddressLine>
            <AddressLine>Rosebank</AddressLine>
            <AddressLine>Houghton</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Wayne</Firstname>
        <Surname>Farmey</Surname>
        <Telephone>0117453269</Telephone>
        <Address>
            <AddressLine>51 Oak Street</AddressLine>
            <AddressLine>Rivionia</AddressLine>
            <AddressLine>Sandton</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
    <Person>
        <Firstname>Mark</Firstname>
        <Surname>Jones</Surname>
        <Telephone>0119854741</Telephone>
        <Address>
            <AddressLine>4 Arum Lane</AddressLine>
            <AddressLine>Glen Hazel</AddressLine>
            <AddressLine>Johannesburg</AddressLine>
            <AddressLine>South Africa</AddressLine>
        </Address>
    </Person>
</Persons>

我知道我需要使用.modify（），但是我不知道如何遍历子节点并将每个子"<person>"节点插入/附加到父"<persons>"节点。 / p>

我认为它需要类似下面的内容

SET @XMLParentData.modify('
    insert     
        (
            sql:variable("@XMLChildData")
        )
    after
        (/Person[1]/Person[1])
')

SELECT @XMLData

Answer 1

将@ Person节点从@XMLChildData提取到单独的变量，并将其添加到Persons的{{1}}节点。

@XMLParentData

另一种方法是从两个变量中提取DECLARE @PersonList XML SET @PersonList = @XMLChildData.query('Persons/*') SET @XMLParentData.modify('insert sql:variable("@PersonList") as last into /Persons[1]') SELECT @XMLParentData个节点，并使用Person重建Persons节点。

FOR XML PATH

SQL Server将XML子节点附加到父节点

1 个答案: