Question

我试图通过使用有效的用户ID修改android HelloMonkey几天来打电话，当我打电话时我收到错误“拨打电话时帐号SID不能为空” 我的代码就像

    public void connect(String phoneNumber) {
    Map<String, String> parameters = new HashMap<String, String>();
    parameters.put("PhoneNumber", phoneNumber);
    if (device == null){
        Log.w("", "Failed device == null");
    }else{
        Log.w("", "device != null");
    }
    connection = device.connect(parameters, null /* ConnectionListener */);
    if (connection == null)
        Log.w(TAG, "Failed to create new connection");
}

没有找到null

请帮忙。提前致谢

Answer 1

使用＆＃34; To＆＃34;而不是使用键名作为＆＃34; PhoneNumber＆＃34;作为Map参数的关键。

public void connect(String phoneNumber) {
    Map<String, String> parameters = new HashMap<String, String>();
    parameters.put("To", phoneNumber);
    connection = device.connect(parameters, null /* ConnectionListener */);
    if (connection == null)
        Log.w(TAG, "Failed to create new connection");
}

Twilio Client for android

Android Twilio拨打电话

1 个答案: