Question

我正在使用Zombie.js构建一个小应用程序，但选项卡似乎无法正常工作。我目前的代码如下：

// libs used
var Zombie = require("zombie");
var assert = require("assert");
var http = require('http');
var express = require('express');
var bodyParser = require('body-parser');

// server port and host configs
var server_port = 7777;
var server_ip_address = '127.0.0.1'

var app = express();
var httpServer = http.Server(app);

app.use( bodyParser.json() );       // to support JSON-encoded bodies
app.use( bodyParser.urlencoded() ); // to support URL-encoded bodies

// o navegador
var browser = null,
    result = "",
    SITE_URL = 'http://en.wikipedia.org/wiki/Programming_language';

app.get('/', function (response, request) {
  console.log('GET request received.');
  console.log('Opening new tab: ' + SITE_URL);
  // opens a tab
  browser.open(SITE_URL);
  // gets page content
  result = browser.html('#content');
  console.log('Tab open: '+browser.tabs.index);
  console.log('Content: '+result);
  request.send(result);
});

httpServer.listen(server_port, server_ip_address, function() {
  console.log('Listening on ' + server_ip_address + ':' + server_port);
  // creates the browser.
  browser = new Zombie();
});

但browser.html('#content');没有任何回报。在我看来，这些选项卡是打开的，但是当我尝试从当前打开的选项卡中提取数据时，通过使用浏览器对象，它永远不会起作用。我做得对吗？什么是在Zombie 2.0.8中使用标签的“正确方法”？我无法找到任何信息/教程，而且官方文档对我来说还不够清楚。

修改

正如P.scheit指出的，open（url）还不够。下面是主要的结果代码：

app.get('/', function (request, response) {
  console.log('GET request received.');
  if (request.query.url && request.query.selector) {
    console.log('Opening new tab: ' + request.query.url);
    browser.open(request.query.url);
    browser.visit(request.query.url, function () {
      result = browser.html(request.query.selector);
      console.log('Loaded tab content. Sending back to user...');
      response.send(result);
    });
    console.log('Tab open: '+browser.tabs.index);
  } else if (request.query.tabid && request.query.selector) {
    var tabid = request.query.tabid;
    if (tabid < browser.tabs.length) {
      browser.tabs.current = tabid;
      console.log('Retrieving content of tab '+tabid+", sending back to user...");
      result = browser.html(request.query.selector);
      response.send(result);
    } else {
      console.log('Tab not found!');
      response.send('Tab not found!');
    }
  } else {
    console.log('Supply either [(the tab id) AND (search selector)] or [(the url to visit) AND (search selector)]!');
    response.send('Supply either [(the tab id) AND (search selector)] or [(the url to visit) AND (search selector)]!');
  }
});

运行服务器后，打开一些标签：

$ curl "http://127.0.0.1:7777/?url=http://en.wikipedia.org/wiki/Programming_language&selector=h1"
$ curl "http://127.0.0.1:7777/?url=http://stackoverflow.com/users/3739186/cyberpunk&selector=h1"
$ curl "http://127.0.0.1:7777/?url=http://www.google.com.br&selector=a"

标签0中的数据：

$ curl "http://127.0.0.1:7777/?tabid=0&selector=a"

Answer 1

在这里疯狂地猜测：你打开标签后尝试使用访问吗？当你传递网址打开时，我不确定僵尸是否正在请求网站。

Zombie + NodeJS + Express - 使用标签时出错

1 个答案: