Question

我有一个文本文件，其中包含：
xxx_123
XXX_001
xxx_345
YYY_123
ZZZ_789
ZZZ_123

我想返回一个列表：
xxx_345
YYY_123
ZZZ_789

for item in list1:
    item = item.split("_")
    part1 = item[0]
    part2 = item[1]

    for line in list1:
        line = line.split("_")
        Bpart1 = line[0]
        Bpart2 = line[1]

        if part1 == Bpart1:
            if part2>Bpart2:
                print item
        else:
            print "Items do not match"

有什么想法吗？

Answer 1

你无法一次性完成，所以你需要保留结果：

from collections import defaultdict
cache = defaultdict(int)

for item in list1:
    item = item.split("_")
    key = item[0]
    value = int(item[1])

    if cache[key] < value:
        cache[key] = value

for k, v in cache.items():
    print("{}_{}".format(k, v))

Answer 2

from collections import OrderedDict

list1 = ['xxx_123', 'xxx_001', 'xxx_345', 'YYY_123', 'ZZZ_789', 'ZZZ_123']

d = OrderedDict()

for item in list1:
    part1, part2 = item.split('_', 1)
    part2 = int(part2)

    if d.setdefault(part1, part2) < part2:
        d[part1] = part2

for key, value in d.iteritems():
    print '{}_{}'.format(key, value)

# xxx_345
# YYY_123
# ZZZ_789

Answer 3

我目前有这个：

cache = defaultdict()
for item in list1:
    item= item.split('_')
    part1 = item[0]
    part2 = int(item[1])
if cache.setdefault(part1,part2)<part2:
    cache[part1] = part2
    for part1,part2 in cache.iteritems():
        line = "%s_%s"%(part1,part2)
        print line

从列表中删除较小的值

3 个答案: