Question

我在将json数组连接到json对象时遇到问题

我运行查询以获取有关所选部件的详细信息，该部件仅返回一个结果（预期）。然后我运行另一个查询来查找与第一个父部件相关的任何部件。这可能不返回任何或多个相关部分。我希望我的最终输出看起来像这样：

{
  "partCode": "P1",
  "description": "The Parent Part",
  "active": "1",
  "partType": "1",
  "partGroup": "BLR",
  "qty": "1",
  "page": "boiler",
  "relatedParts": [
       {
          "partCode": "P2",
          "description": "some related part",
          "active": "1",
          "partType": "1",
          "partGroup": "BLR",
          "qty": "1"
        },
        {
          "partCode": "P3",
          "description": "Another related part",
          "active": "1",
          "partType": "1",
          "partGroup": "BLR",
          "qty": "1"
        }
      ]
}

如何将相关的parts []数组添加到json {}对象中？

我的疑问是：

//parent part
$query= "SELECT * FROM `parts`
  INNER JOIN `partPrice` ON `parts`.`partCode` = `partPrice`.`partCode`
WHERE `parts`.`partCode` = '$part' AND `partPrice`.`active` = 1;";

$result = mysql_query($query);
if (!$result) {
  die("Invalid query: " . mysql_error());
}

$json=array();
$relatedParts=array();

if (mysql_num_rows($result)>0){
    while($row=mysql_fetch_assoc($result)){ 
        $json[]=$row; 
        $json['relatedParts']=$relatedParts;
    }
}

//get MANADTORY related parts
$query= "SELECT parts.*
FROM
  partAssociation
  INNER JOIN parts ON partAssociation.childPart = parts.partCode
WHERE
  partAssociation.parentPart = '$part' AND
  partAssociation.association = 'Requires';";


$result = mysql_query($query);
if (!$result) {
  die("Invalid query: " . mysql_error());
}

$json2=array();

if (mysql_num_rows($result)>0){
    while($row=mysql_fetch_assoc($result)){ 
        $json2[]=$row;

    }
}
$json['relatedParts']=$json2;

echo json_encode( $json);

编辑：找到一个可能不完美但有效的解决方案; 首先获取相关记录，然后将该结果添加到父记录中仍然会对任何更加光滑的方式感兴趣。

//get MANDATORY related parts
$query2 = "SELECT parts.*
FROM
  partAssociation
  INNER JOIN parts ON partAssociation.childPart = parts.partCode
WHERE
  partAssociation.parentPart = '$part' AND
  partAssociation.association = 'Requires';";

//set the holders 
$json=array();
$relatedParts=array();

//get any related records first
$resultRP = mysql_query($query2);
if (!$resultRP) {
  die("Invalid query: " . mysql_error());
}

if (mysql_num_rows($resultRP)>0){
    while($row=mysql_fetch_assoc($resultRP)){ 
        $relatedParts[]=$row;       
    }
}

//get parent record  
$result = mysql_query($query1);
if (!$result) {
  die("Invalid query: " . mysql_error());
}

if (mysql_num_rows($result)>0){
    while($row=mysql_fetch_assoc($result)){ 
        $row['relatedParts']=$relatedParts;
        $json[]=$row;
    }
}


echo json_encode($json);

将json数组合并到json对象中

0 个答案: