Question

我有SQL数据库

包含列：

ID - 名称 - 价格 - 类别 - 计数 - 颜色 - First_Litter

示例：

1 - Test1 - 10 - Test1 - 0 - Yellow - T

2 - Test2 - 12 - Test2 - 2 - Red - T

3 - Test3 - 15 - Test3 - 7 - Green - T

4 - Cast1 - 15 - Cast1 - 5 - Blue - C

我希望使用First_Litter获取此联系人我有这个代码，通过ID获取项目项目并且工作正常

    public Items getContact(int id) {
    SQLiteDatabase db = this.getReadableDatabase();

    Cursor cursor = db.query(TABLE_CONTACTS, new String[] { KEY_ID,
            KEY_NAME, KEY_PRICE, KEY_CATEGORY,KEY_COUNT,KEY_BGC,KEY_FL }, KEY_ID + "=?",
            new String[] { String.valueOf(id) }, null, null, null, null);
    if (cursor != null)
        cursor.moveToFirst();

    Items contact = new Items(Integer.parseInt(cursor.getString(0)),cursor.getString(1), cursor.getString(2), cursor.getString(3), cursor.getString(4), cursor.getString(5), cursor.getString(6));
    // return contact
    return contact;
}

我将这段代码编辑了一下，以获得First Litter的getContact

    public Items getContactFL(String fl) {

        SQLiteDatabase db = this.getReadableDatabase();

        Cursor cursor = db.query(TABLE_CONTACTS, new String[] { KEY_ID,
                KEY_NAME, KEY_PRICE, KEY_CATEGORY,KEY_COUNT,KEY_BGC,KEY_FL }, KEY_FL + "=?",
                new String[] { fl }, null, null, null, null);
        if (cursor != null)
            cursor.moveToFirst();

        Items contact = new Items(Integer.parseInt(cursor.getString(0)),cursor.getString(1), cursor.getString(2), cursor.getString(3), cursor.getString(4), cursor.getString(5), cursor.getString(6));
        // return contact
        return contact;
    }

但它不起作用，它只给我1个项目

我需要当我做getContactFL（＆＃34; A＆＃34;）时，告诉我所有项目在FirstLitter列中有A

有人可以帮助我，抱歉我的英语不好

Answer 1

我不认为你是first_letter的专栏......你可以这样做......

String Query="SELECT * FROM "+TABLE_CONTACTS+" WHERE "+KEY_NAME+" LIKE '%"+f1+"%'";
Cursor Cursor=db.rawQuery(Query, null);

确定更改代码

if (cursor != null)
        cursor.moveToFirst();

    Items contact = new Items(Integer.parseInt(cursor.getString(0)),cursor.getString(1), cursor.getString(2), cursor.getString(3), cursor.getString(4), cursor.getString(5), cursor.getString(6));
    // return contact
    return contact;

到

Items[] contact=new Items[cursor.getCount()];
int i=0;cursor.moveToFirst();
while (!cursor.isAfterLast())
{
    contact[i++] = new Items(Integer.parseInt(cursor.getString(0)),cursor.getString(1), cursor.getString(2), cursor.getString(3), cursor.getString(4), cursor.getString(5), cursor.getString(6));
    cursor.moveToNext();
}
    return contact;

Answer 2

尝试这样，可以帮助你 public Items getContactFL（String fl）{

        SQLiteDatabase db = this.getReadableDatabase();

        Cursor cursor = db.query(TABLE_CONTACTS, new String[] { KEY_ID,
                KEY_NAME, KEY_PRICE, KEY_CATEGORY,KEY_COUNT,KEY_BGC,KEY_FL }, KEY_FL + "=?",
                new String[] { fl }, null, null, null, null);

 if (cursor.moveToFirst()) {
                  //put your item code here
 }

 if (cursor != null && !cursor.isClosed()) {
            cursor.close();
  }

    // return contact
    return contact;
}

android sql getContact by name first character

2 个答案: