Question

我正在尝试学习spring-ws并从本教程开始： http://spring.io/guides/gs/producing-web-service/#initial

我现在要做的是通过以编程方式配置应用程序来启动非嵌入式servlet容器上的服务。

我不知道如何在没有web.xml的情况下设置Message Dispatcher Servlet。我试图做的是实现WebApplicationInitializer接口的onStartup方法（ServletContext servletContext）。

public class ServerInitializer  implements WebApplicationInitializer{

    public void onStartup(ServletContext servletContext) throws ServletException {

        AnnotationConfigWebApplicationContext context = new AnnotationConfigWebApplicationContext();
        context.setConfigLocation(WebServiceConfig.class.getName());
        servletContext.addListener(new ContextLoaderListener(context));

        MessageDispatcherServlet servlet = new MessageDispatcherServlet();
        servlet.setApplicationContext(context);
        servlet.setTransformWsdlLocations(true);


        // Create dispatcher for named context
        ServletRegistration.Dynamic dispatcherServlet = servletContext.addServlet("DispatcherServlet", servlet);

        // Load on startup
        dispatcherServlet.setLoadOnStartup(1);

        // Add URL mapping for dispatcher
        dispatcherServlet.addMapping("/*");


    }

}

但是，当我将其部署到tomcat时，我使用SOAP UI（正在处理教程示例）发送的请求永远不会被映射

Answer 1

这就是我最终的工作方式：

public class WebServiceInitializer implements WebApplicationInitializer {

    private static final String ACTIVE_PROFILE = "production";

    /**
     * Registers and loads on startup MessageDispatcherServlet for the SOAP messages
     */
    @Override
    public void onStartup(ServletContext servletContext) throws ServletException {

        AnnotationConfigWebApplicationContext context = new AnnotationConfigWebApplicationContext();

        // @EnableWs, @Configuration, @ComponentScan
        context.setConfigLocation(WebServiceBeans.class.getName());
        context.getEnvironment().setActiveProfiles(ACTIVE_PROFILE);

        // use MessageDispatcherServlet instead of standard DispatcherServlet for SOAP messages
        MessageDispatcherServlet servlet = new MessageDispatcherServlet();
        servlet.setContextClass(AnnotationConfigWebApplicationContext.class);
        servlet.setApplicationContext(context);
        servlet.setTransformWsdlLocations(true);

        // register MessageDispatcherServlet as Web Service entry point
        final ServletRegistration.Dynamic dispatcher = servletContext.addServlet("MessageDispatcherServlet",
                servlet);

        dispatcher.setLoadOnStartup(1);
        dispatcher.addMapping("/*");
    }

编辑 //添加了正确的方法，以前的答案有很多冗余。

Answer 2

扩展AbstractAnnotationConfigDispatcherServletInitializer并实现3个剩余方法 +在onStartup

中添加自己的servlet

import org.springframework.web.servlet.support.AbstractAnnotationConfigDispatcherServletInitializer;

public class WebAppInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {

    @Override
    protected String[] getServletMappings() {
        return new String[] { "/*" };
    }

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class<?>[] { RootContextConfiguration.class, SecurityConfiguration.class };
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return new Class<?>[] { WebConfiguration.class };
    }

    @Override
    public void onStartup(final ServletContext servletContext) throws ServletException {
        super.onStartup(servletContext);
        final ServletRegistration.Dynamic dispatcher = servletContext.addServlet("someotherServlet",
                new DispatcherServlet(context));
        dispatcher.setLoadOnStartup(1);
        dispatcher.addMapping("/*");
    }

}

如何以编程方式配置MessageDispatcherServlet

2 个答案: