Question

int guess_number = (gen() % 1000);
cout << guess_number;

int number = 0;
cout << "Number:";
cin >> number;

do
{
    if (number>guess_number)
    {
        cout << "Too High"<<"\n";
        cin >> number;
    }
    else if (number<guess_number)
    {
        cout << "Too Low"<< "\n";
        cin >> number;
    }
} while (number != guess_number);
  int again=0;  
  cout << "Wanna Play Again!";
  cin >> again;

我正在制作一个猜谜游戏，但如果玩家在“再玩一次”之后回答1，则必须循环游戏！＆＃34;我正在使用if，for，do，switch和while语句。它是我给出的一项任务，而我似乎无法弄清楚如何循环其中的内容。我做了几次尝试，但要么退出程序要么不断打印＆＃34;想要再玩一次！＆＃34;。

Answer 1

如何将现有的do / while包含在另一个中再次播放条件？

int again =0;
do{ 
  do{
     //existing code
  } //end inner while
  cout << "Wanna Play Again?";
  cin >> again;
} while(again != 0); //or whatever makes sense for the condition

循环语句完成后如何循环？

1 个答案: