你想继续（y / n）问题吗？

Question

是否要继续（y / n）在此c代码中不起作用。我希望它在我输入'y'时输入一个字符串，如果输入n，则退出程序。我尝试了很多选择，但无济于事。 谢谢你的帮助

    do
    {
        i = 0, final = 0, s = 0;
        printf("\n\nEnter Input String.. ");
        scanf("%s", string);

        while (string[i] != '\0')
            if ((s = check(string[i++], s)) < 0)
                break;
        for (i = 0 ; i < nfinals ; i++)
            if (f[i] == s )
                final = 1;
        if (final == 1)
            printf("\n String is accepted");
        else
            printf("String is rejected");

        printf("\nDo you want to continue.?  \n(y/n) ");
    }
    while (getch() == 'y');

    return getch();
}

Answer 1

if (getch() == 'n') {
    // print something
    return;
}

Answer 2

在将char作为输入之前应该刷新缓冲区

do
{//..your code
printf("\nDo you want to continue.?  \n(y/n) ");
scanf("%c",&ch);
scanf("%c",&ch);
}
while (ch == 'y');