Question

我需要删除表中的所有记录，其间的时间介于1或2分钟之间或相同且必须相同ID但保留第一条记录

ID             Time             SN  SD   WE FW
10  2014-06-30 19:17:37.000 I   0   100 0
10  2014-06-30 19:17:42.000 I   0   100 0
10  2014-06-30 19:17:46.000 I   0   100 0
10  2014-06-30 19:17:58.000 I   0   100 0
10  2014-06-30 20:37:46.000 I   0   100 0

或

ID             Time             SN  SD   WE FW
10  2014-07-01 21:10:33.000 I   0   100 0
10  2014-07-01 21:11:06.000 O   0   100 0
10  2014-07-02 20:53:36.000 I   0   100 0
10  2014-07-02 20:53:38.000 I   0   100 0
10  2014-07-02 20:54:33.000 O   0   100 0
10  2014-07-02 20:54:41.000 O   0   100 0
10  2014-07-02 20:55:22.000 o   0   100 0

是

ID             Time             SN  SD   WE FW
10  2014-06-30 19:17:37.000 I   0   100 0
10  2014-06-30 20:37:46.000 I   0   100 0

和

ID             Time             SN  SD   WE FW
10  2014-07-01 21:10:33.000 I   0   100 0
10  2014-07-02 20:53:36.000 I   0   100 0

ITS无法正常工作 抱歉，我是新的@sql这个MY Table内容

SELECT TOP 1000 
      [USERID]
      ,[CHECKTIME]
      ,[CHECKTYPE]
      ,[VERIFYCODE]
      ,[SENSORID]
      ,[WorkCode]
      ,[sn]
FROM 
   [NEWFP].[dbo].[CHECKINOUT]

我需要删除时间为2或1分钟的记录并保留第一个但用户ID相同的记录。

我不能这样做？

Answer 1

你走了！

DECLARE @Seconds INT = 120
DECLARE @Logs TABLE (
    ID INT,
    [Time] DATETIME
)
INSERT @Logs VALUES
(10, '2014-06-30 19:17:37.000'),
(10, '2014-06-30 19:17:42.000'),
(10, '2014-06-30 19:17:46.000'),
(10, '2014-06-30 19:17:58.000'),
(10, '2014-06-30 20:37:46.000'),
(10, '2014-07-01 21:10:33.000'),
(10, '2014-07-01 21:11:06.000'),
(10, '2014-07-02 20:53:36.000'),
(10, '2014-07-02 20:53:38.000'),
(10, '2014-07-02 20:54:33.000'),
(10, '2014-07-02 20:54:41.000'),
(10, '2014-07-02 20:55:22.000')

;WITH Logs AS (
    SELECT
        ID,
        [Time],
        ROW_NUMBER() OVER (PARTITION BY ID ORDER BY [Time]) AS RowNum
    FROM @Logs L
)
    --SELECT *, DATEDIFF(SS, L1.[Time], L2.[Time])
    DELETE L2
    FROM Logs L1
        INNER JOIN Logs L2
            ON L1.ID = L2.ID
                AND L1.RowNum = L2.RowNum - 1
    WHERE DATEDIFF(SS, L1.[Time], L2.[Time]) < @Seconds
SELECT * FROM @Logs

Answer 2

对于您的特定表格，请尝试以下代码。它假设USERID是＆＃34; ID＆＃34;从你原来的问题和CHECKTIME是＆＃34;时间＆＃34;。希望这对你有用！

DECLARE @Seconds INT = 120
;WITH Logs AS (
    SELECT
        [USERID] AS ID,
        [CHECKTIME] AS [Time],
        ROW_NUMBER() OVER (PARTITION BY ID ORDER BY [Time]) AS RowNum
    FROM [NEWFP].[dbo].[CHECKINOUT] L
)
    DELETE L2
    FROM Logs L1
        INNER JOIN Logs L2
            ON L1.ID = L2.ID
                AND L1.RowNum = L2.RowNum - 1
    WHERE DATEDIFF(SS, L1.[Time], L2.[Time]) < @Seconds

删除部分原始副本的记录

2 个答案: