Question

function subKategori($str){
    global $koneksi;
    $A = $str;

    $A1 = mysqli_query($koneksi, "select * from kategori where sub_id='".$A."'");
    $A2 = mysqli_num_rows($A1);
    if($A2 != 0){
        while($A3 = mysqli_fetch_array($A1)){
            $query1 = 'or id_kategori='.$A3['id'].' ';
            $query = ''.subKategori($A3['id']).' '.$query1.' '; //variable 1
        }
    }else{}
}


$idKategori = 1;
subKategori($idKategori);
$output = $query; //output variable 1

我想从外面获取变量...
因为，如果我使用subKategori（）;在mysqli_query（）上，它显示了......

像

mysqli_query($connection, "Select * from item where id_category="'.$idKategori."' $output");

Answer 1

return是你的朋友。

function Test(){
  return "AAAAHHH";
}

Echo Test(); // Output "AAAAHHH"

PHP在function（）下得到变量

1 个答案: