使用php将两个csv文件合并在一起

时间:2014-10-18 14:31:37

标签: php csv

我有两套csv文件 - 一组包含合同数据,另一组包含授予的合同。我需要使用公共字段(contractName)合并两个csv文件,并计算已结算的合同总额。Link to the csv files

到目前为止,我已经设法将两个csv文件合并在一起并将其写入final.csv文件中,但我无法使用公共字段(contractName)合并两个csv文件。这是代码。

<?php
$nn = 0;
foreach (glob("*.csv") as $filename) {
    if (($handle = fopen($filename, "r")) !== FALSE) {
        while (($data = fgetcsv($handle, 0, ",")) !== FALSE) {

            $c = count($data);

            for ($x=0;$x<$c;$x++)
            {
                $csvarray[$nn][] = $data[$x];
            }
            $nn++;
        }

        fclose($handle);
    }

}

$fp = fopen('../final.csv', 'w');//output file set here

foreach ($csvarray as $fields) {
    fputcsv($fp, $fields);
}

fclose($fp);?>

这是我的最终输出。

contractName,contractDate,completionDate,awardee,awardeeLocation,Amount
Contract-2070-3,5/9/14,8/25/14,"SK Builders",Banke,200000
Contract-2070-5,3/18/14,4/8/14,"S engineering industries",Makwanpur,300000
Contract-2070-9,3/6/14,4/6/14,"Gourishankar nirman sewa",Lalitpur,400000
Contract-2070-10,2/6/14,6/16/14,"SK Builders",Banke,500000
contractname,status,bidPurchaseDeadline,bidSubmissionDeadline,bidOpeningDate,tenderid,publicationDate,publishedIn
Contract-2070-1,Closed,6/12/14,6/13/14,6/13/14,2070/071/2,5/14/14,"Nagarik Daily"
Contract-2070-2,Closed,6/10/14,6/11/14,6/11/14,16/070/71,5/12/14,"The Himalayan Times"
Contract-2070-3,Current,3/8/14,3/9/14,3/9/14,DDC/Bag/Bridge/03-070/71,3/10/14,"Nagarik Daily"
Contract-2070-4,Current,4/23/14,4/25/14,4/25/14,04(2070/071),4/9/14,"Hetauda sandesh"
Contract-2070-5,Closed,4/23/14,4/25/14,4/26/14,04(2070/071),4/10/14,"Hetauda sandesh"
Contract-2070-6,Current,4/23/14,4/25/14,4/27/14,04(2070/071),4/11/14,"Hetauda sandesh"
Contract-2070-7,Current,4/23/14,4/25/14,4/28/14,04(2070/071),4/12/14,"Hetauda sandesh"
Contract-2070-8,Current,4/23/14,4/25/14,4/29/14,04(2070/071),4/13/14,"Hetauda sandesh"
Contract-2070-9,Closed,2/6/14,2/8/14,2/8/14,15/070/71,1/9/14,"The Himalayan Times"
Contract-2070-10,Current,1/14/14,1/15/14,1/16/14,"13,2070/2071",1/6/14,"The Himalayan Times"

但最终输出应该是这样的。

contractname,status,bidPurchaseDeadline,bidSubmissionDeadline,bidOpeningDate,tenderid,publicationDate,publishedIn,contractDate,completionDate,awardee,awardeeLocation,Amount 
Contract-2070-1,Closed,6/12/14,6/13/14,6/13/14,2070/071/2,5/14/14,Nagarik Daily,,,,,
Contract-2070-2,Closed,6/10/14,6/11/14,6/11/14,16/070/71,5/12/14,The Himalayan Times,,,,,
Contract-2070-3,Current,3/8/14,3/9/14,3/9/14,DDC/Bag/Bridge/03-070/71,3/10/14,Nagarik Daily,5/9/14,8/25/14,SK Builders,Banke,200000
Contract-2070-4,Current,4/23/14,4/25/14,4/25/14,04(2070/071),4/9/14,Hetauda sandesh,,,,,
Contract-2070-5,Closed,4/23/14,4/25/14,4/26/14,04(2070/071),4/10/14,Hetauda sandesh,3/18/14,4/8/14,S engineering industries,Makwanpur,300000
Contract-2070-6,Current,4/23/14,4/25/14,4/27/14,04(2070/071),4/11/14,Hetauda sandesh,,,,,
Contract-2070-7,Current,4/23/14,4/25/14,4/28/14,04(2070/071),4/12/14,Hetauda sandesh,,,,,
Contract-2070-8,Current,4/23/14,4/25/14,4/29/14,04(2070/071),4/13/14,Hetauda sandesh,,,,,
Contract-2070-9,Closed,2/6/14,2/8/14,2/8/14,15/070/71,1/9/14,The Himalayan Times,3/6/14,4/6/14,Gourishankar nirman sewa,Lalitpur,400000
Contract-2070-10,Current,1/14/14,1/15/14,1/16/14,"13, 2070/2071",1/6/14,The Himalayan Times,2/6/14,6/16/14,SK Builders,Banke,500000

2 个答案:

答案 0 :(得分:1)

这个问题不是很难,你总是可以把数据放在数组的csv上并使用它们,就像这个解决方案一样:

// 1st section
        $fh = fopen('awards.csv', 'r');
        $fhg = fopen('contracts.csv', 'r');
         while (($data = fgetcsv($fh, 0, ",")) !== FALSE) {
            $awards[]=$data;
        }
        while (($data = fgetcsv($fhg, 0, ",")) !== FALSE) {
                $contracts[]=$data;
        }
 // 2nd section   
        for($x=0;$x< count($contracts);$x++)
        {
            if($x==0){
                unset($awards[0][0]);
                $line[$x]=array_merge($contracts[0],$awards[0]); //header
            }
            else{
                $deadlook=0;
                for($y=0;$y <= count($awards);$y++)
                {
                    if($awards[$y][0] == $contracts[$x][0]){
                        unset($awards[$y][0]);
                        $line[$x]=array_merge($contracts[$x],$awards[$y]);
                        $deadlook=1;
                    }           
                }
                if($deadlook==0)
                    $line[$x]=$contracts[$x];
            }
        }
  // 3 section     
        $fp = fopen('final.csv', 'w');//output file set here

        foreach ($line as $fields) {
            fputcsv($fp, $fields);
        }
        fclose($fp);

我很难解释这段代码,因为来自一个西班牙国家,所以我的英语不是很好......但我可以试试

基本上代码有3个部分,

在第1节中, 打开这两个文件并将内容放入数组$ awards []和$ contracts []中,因此$ awards [0]是awards.csv中的第一行,$ awards [1]是awards.csv中的第二行,等,在$ contracts []中也一样。

在第2部分,

我比较每个数组中的第一个单词,$ awards [x] [0]和$ contracts [x] [0]。

第一个if,if($ x == 0),是要制作标题。 首先,我使用contractname函数删除第一个单词unset,并使用array_merge函数加入$ awards [0]和$ contracts [0]。

然后,使用那些for我从$ contracts数组的每一行中选择第一个单词,并与$ awards数组中每一行的第一个单词进行比较。 所以,if($awards[$y][0] == $contracts[$x][0])检查那些第一个单词(ej。Contract-2070-3are)是否相同,如果它们是相同的字符串,删除它并合并这些行。

如果这些单词不相同,请在$ line数组中保存$ contracts [x]行并继续。

在第3节中, 保存文件中$ line数组的内容。

答案 1 :(得分:0)

这是某种面试问题吗?您是否需要显示编写算法的能力或以实际方式解决问题?

对于大数据集,我可能只是将csv转储到sqlite数据库,每个csv一个表,并将它们与查询连接起来。

或者你可以用每个csv,$ contracts和$ awards填充两个关联数组,使用连接字段(contractName)作为两个数组的关键字。
然后你打破键,并用给定键的每个数组的内容填充$ final数组:

$final = array();
$keys = array_keys($contracts);
foreach($keys as $key) {
    $final[] = array_merge($contracts[$key], $awards[$key]);
}