我的动机:在逐渐增加时间之后调用函数说XYZ()。
first time after 3 secs,
second time:6 secs
third time: 12secs
这应该发生在页面上..页面A,B,C 页面第一个弹出窗口然后他浏览页面B然后时间应该增加/加倍
我知道setInterval
函数..但我很困惑如何使用它..
1)制作新的js并调用主文件
2)在所有页面中编写脚本。
答案 0 :(得分:0)
//Following code may help you
//using cookie we are handing navigation count
function createCookie(name, value, days) {
if (parseInt(days, 10)) {
var date = new Date();
date.setTime(date.getTime() + (days * 24 * 60 * 60 * 1000));
var expires = "; expires=" + date.toGMTString();
} else {
expires = "";
}
document.cookie = name + "=" + escape(value) + expires + "; path=/";
}
// copied from http://lea.verou.me/2009/12/reading-cookies-the-regular-expression-way/
function readCookie(name) {
name = name.replace(/([.*+?^=!:${}()|[\]\/\\])/g, '\\$1');
var regex = new RegExp('(?:^|;)\\s?' + name + '=(.*?)(?:;|$)', 'i'), match = document.cookie.match(regex);
return match && unescape(match[1]);
}
var navcountval;
if (!readCookie("navcount")) {
navcountval = 1;
createCookie("navcount", 1, 365);
} else {
navcountval = readCookie("navcount");
navcountval = parseInt(navcountval) + 1;
createCookie("navcount", navcountval, 365);
}
// your code for of setTimeout based on pagenavcount * seconds like "navcountval * 3sec"
答案 1 :(得分:0)
您必须在每个网页中包含此javascript,这应该达到我认为您要实现的目标。此脚本每3秒将“timeTracker”cookie的值加倍
function updateInterval() {
var pageCookies = document.cookie.split(';');
var lastValueOfTimeTracker = 3;
for(var i=0; i< pageCookies.length; i++) {
var currentCookie = pageCookies[i].split(',');
if(currentCookie[0].indexOf('timeTracker') != -1) {
var temp = currentCookie[0].split('=');
alert(temp[1]);
lastValueOfTimeTracker = temp[1];
}
}
document.cookie = 'timeTracker=' + (lastValueOfTimeTracker * 2);
}