Question

如何在listview中获取所选项目，我有listview与arrayadapter，listview包含26项，但我只需显示6项，另一项显示在更多按钮。我怎么能得到这个。请帮我。在此先感谢.....！

MainActivity.java

公共类SelectProtocolActivity扩展了Activity {

ListView listview;
ListViewArrayAdapter arrayadapter;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main_activity);

listview = (ListView) findViewById(R.id.protocol_list_view);
db = DatabaseHelper.getHelper(getApplicationContext());
        protocols = db.getAllProtocolsList();
        arrayadapter = new ListViewArrayAdapter(this, protocols);
        listview.setAdapter(arrayadapter);





listview.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> adapter, View view, int position, long id){

        }
        });
    }

}

ListViewArrayAdapter.java

public class ListViewArrayAdapter extends BaseAdapter implements ListAdapter {

    private final Activity activity;
    private final List<Item> itemList;

    ProtocolArrayAdapter(Activity activity, List<Items> itemList) {
        assert activity != null;
        assert protocolList != null;

        this.itemList = itemList;
        this.activity = activity;
    }

    @Override
    public int getCount() {
        if (null == itemList)
            return 0;
        else
            return itemList.size();
    }

    @Override
    public Item getItem(int position) {
        if (null == itemList)
            return null;
        else
            return itemList.get(position);
    }

    @Override
    public long getItemId(int position) {
        //Protocol protocol = getItem(position);

        return position;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        if (convertView == null)
            convertView = activity.getLayoutInflater().inflate(R.layout.item_list_item, null);

        TextView tvItemName = (TextView) convertView.findViewById(R.id.item_name);

        Item item = getItem(position);
        if (null != item) {
            try {
                tvItemName.setText(item.getName());
            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }

        return convertView;
    }
}

Answer 1

请仔细阅读希望说明帮助您

您可以通过多种方式实现可以在此处使用可扩展列表视图或

的东西

我认为你为那个Bean类加了一个布尔变量名（isOpen）。默认情况下，值为false 应用点击事件查看更多按钮根据

设计行项目XML

分隔布局中的6个项目和分开的20个项目。

20项目布局可见性默认为GONE

比列表视图中点击查看更多根据位置设置isOpen = true 和notifydata设置改变。

并在适配器中进行参数化设置isOpen = true您的20项布局是可见的其他副作用

如何在listview中获取特定项目

1 个答案: