我想在这种情况下问这个循环，在这种情况下问他们一个问题＆＃34;＆＃34;什么是2 + 2？＆＃34;然后接受输入，然后程序应该询问＆＃34;你确定Y / N＆＃34;如果他们没有我想要它回到这个循环的开始并允许他们重做问题。因为它是我无法循环，在这部分工作后，我将需要以相同的格式再做9个问题
import java.util.Scanner;
class Quiz
{
public static void main (String[] args)
{
int q1=0 , q2=0;
boolean correct = false;
char yn1='y';
String q3 , q4;
Scanner input1 = new Scanner( System.in );
int count = 0 ;
//Question 1 start
while (correct == false)
{
System.out.println("What is 2+2? ");
System.out.println("Choices: 0,2,4,8");
q1 = input1.nextInt(); //used after loop
System.out.println("Are You Sure? (y/n)");
char c = input1.next().charAt(0); // Changed LINE
if (c=='y') // Changed LINE
{
if ( q1 == 4) //q1 was stated during loop
System.out.println("You were correct 2+2 = 4");
else
System.out.println("You were wrong");
break;
}
}
//Question 2 start
while (correct == false)
{
System.out.println("how many legs does a legless cow have?");
System.out.println("Choices: 0,25,4,31");
q2 = input1.nextInt();
System.out.println("Are You Sure? (y/n)");
char c = input1.next().charAt(0);
if (c=='y')
{
if ( q2 == 0)
System.out.println("You were correct, the cow has 0 legs");
else
System.out.println("You were wrong");
break;
}
}
//Question 3 start
while (correct == false)
{
System.out.println("What is the capital city of Canada?");
System.out.println("Choices: Toronto, Montreal, Vancouver, Ottawa (capitals count)");
q3 = input1.nextLine();
System.out.println("Are You Sure? (y/n)");
char c = input1.next().charAt(0);
if (c=='y')
{
if ( "Ottawa".equals(q3))
System.out.println("You were correct, The capital is Ottawa");
else
System.out.println("You were wrong");
break;
}
}
}
}
出现了一个新问题我已经使用了一个有用的示例，并且可能会尝试将其更改为数组，但之后不会将其更改为基础工作。到目前为止所有使用int工作的问题即使用。
//Question 1 start
while (correct == false)
{
System.out.println("What is 2+2? ");
System.out.println("Choices: 0,2,4,8");
q1 = input1.nextInt(); //used after loop
System.out.println("Are You Sure? (y/n)");
char c = input1.next().charAt(0); // Changed LINE
if (c=='y') // Changed LINE
{
if ( q1 == 4) //q1 was stated during loop
System.out.println("You were correct 2+2 = 4");
else
System.out.println("You were wrong");
break;
}
}
但是现在我想使用一个单词awnser所以我创建了一个字符串并将其放入而不是int但是现在不是允许输入q3而是跳过输入y / ni不要理解为什么所有的突然它会这样做，但其他问题可以正确使用int。
while (correct == false)
{
System.out.println("What is the capital city of Canada?");
System.out.println("Choices: Toronto, Montreal, Vancouver, Ottawa (capitals count)");
String q3 = input1.nextLine();
System.out.println("Are You Sure? (y/n)");
char c = input1.next().charAt(0);
if (c=='y')
{
if ( "Ottawa".equals(q3))
System.out.println("You were correct, The capital is Ottawa");
else
System.out.println("You were wrong");
break;
}
}
对不起，如果这还没有足够的详细信息或格式错误的话，请务必修复它。
答案 0 :(得分：1)
阅读输入时，请始终使用q1 = Integer.parseInt(input1.nextLine());（更好的是，使用BufferedReader类）。这样，您的阅读将顺利进行。
其次，您可以将if (q1 == 4)放在if (yn1.equals("Y"))语句中。如果用户键入了“Y”，则设置correct = true;以继续下一个问题。此外，如果用户的答案是正确的，那么增加正确答案的计数器，否则打印错误。所以循环看起来像这样：
while (correct == false) {
System.out.println("What is 2+2? ");
System.out.println("Choices: 0,2,4,8");
q1 = Integer.parseInt(input1.nextLine());
System.out.println("Are You Sure? (Y/N)");
yn1 = input1.nextLine();
if (yn1.equals("Y")) {
correct = true;
if (q1 == 4) {
System.out.println("You were correct 2+2 = 4");
count++;
} else
System.out.println("You were wrong");
}
}
要考虑的一些事项：
"Choices: 0,2,4,8"，但没有任何内容阻止用户输入3或3000。选择陈述是否必要？然后，您还需要检查用户是否已进入该范围内。 而不是复制＆amp;将这个相同的循环粘贴n次，使用一个数组。有所有问题＆amp;答案现在存储在一些String数组中。像这样：
for (int i = 0; i < questions.length; i++) {
boolean nextQ = false;
while (nextQ == false) {
System.out.println(questions[i]);
String ans = input1.nextLine();
System.out.println("Are You Sure? (Y/N)");
yn = input1.nextLine();
if (yn.equalsIgnoreCase("Y")) {
nextQ = true;
if (ans.equals(answers[i])) {
System.out.println("You were correct " + questions[i]
+ " = " + answers[i]);
count++;
} else
System.out.println("You were wrong");
}
}
}
我将布尔变量correct更改为nextQ以避免混淆。希望能让你朝着正确的方向前进。
答案 1 :(得分：0)
我试图编译你的程序。但是我遇到了一些错误： -
error: variable q1 might not have been initialized
根据我的理解你的问题。这是你想要的程序： -
import java.util.Scanner;
class stack1
{
public static void main (String[] args)
{
int q1=0 , q2 , q3, q4, q5, q6 , q7 ,q8 ,q9 ,q10 , a ;
boolean correct = false;
char yn1='Y';
Scanner input1 = new Scanner( System.in );
int count = 0 ;
while (correct == false)
{
System.out.println("What is 2+2? ");
System.out.println("Choices: 0,2,4,8");
q1 = input1.nextInt(); //used after loop
System.out.println("Are You Sure? (Y/N)");
char c = input1.next().charAt(0); // Changed LINE
if (c=='y') // Changed LINE
{
System.out.println("Exiting the program");
correct = true; //It should now stop the loop and carry on
break;
}
}
if ( q1 == 4) //q1 was stated during loop
System.out.println("You were correct 2+2 = 4");
else
System.out.println("You were wrong");
//Soon will add int score and add 1 each time its correct
// will be using 9 more loops the exact same way
}
}
我已提及所有已更改的行，并附有评论＆＃39; //已更改行＆＃39;
答案 2 :(得分：0)
这是编辑过的问题的答案： -
import java.util.Scanner;
class stack2
{
public static void main (String[] args)
{
int q1=0 , q2 , q3, q4, q5, q6 , q7 ,q8 ,q9 ,q10 , a ;
boolean correct = false;
char yn1='Y';
String s="";
System.out.println(s);
Scanner input1 = new Scanner( System.in );
int count = 0 ;
while (correct == false)
{
System.out.println("What is the capital city of Canada?");
System.out.println("Choices: Toronto, Montreal, Vancouver, Ottawa (capitals count)");
s = input1.nextLine();
System.out.println(s);
System.out.println("Are You Sure? (Y/N)");
char c = input1.next().charAt(0); // Changed LINE
if (c=='y') // Changed LINE
{
System.out.println("Exiting the program");
correct = true; //It should now stop the loop and carry on
break;
}
if (s.equals("Ottawa")) //q1 was stated during loop
System.out.println("You were correct, The capital is Ottawa");
else
System.out.println("You were wrong");
}
//Soon will add int score and add 1 each time its correct
// will be using 9 more loops the exact same way
}
}
进入输入时要小心。应该是“渥太华”。祝你好运