我有一个登录脚本,但是当我继续它时会出现错误:
Undefined property: Users::$host in C:\wamp\www\userlogin\classes\class.database.php on line 8
有4个文件:
<?php
session_start();
include "classes/class.users.php";
if(isset($_POST['login'])) {
$username = $_POST['username'];
$password = $_POST['password'];
$users->login($username, $password);
}
?>
<!DOCTYPE html>
<head>
<title>Basic Login Script</title>
</head>
<body>
<form method="POST" action="" name="login">
<input type="text" name="username">
<input type="password" name="password">
<input type="submit" name="login" value="Login">
</form>
</body>
</html>
<?php
class Database
{
public function __construct()
{
$host = 'localhost';
$user = 'root';
$pass = 'password';
$name = 'usersystem';
$this->mysqli = new mysqli($this->host, $this->user, $this->pass, $this->name);
if ($mysqli->connect_errno)
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
echo $mysqli->host_info . "\n";
}
} ?>
<?php
include "class.database.php";
class Users extends Database
{
public function login($username, $password)
{
$stmt = $this->mysqli->prepare("SELECT username, password FROM users WHERE username = ? and password = ? LIMIT 1");
$stmt->bind_param('ss', $username, $password);
$stmt->execute();
$stmt->bind_result($username, $password);
$stmt->store_result();
if($stmt->num_rows == 1) {
while($stmt->fetch()) {
$_SESSION['username'] == $username;
header("Location: dashboard.php");
}
}
else
return false;
$stmt->close();
$stmt->free_result();
}
}
$users = new users(); ?>
//dashboard
<?php echo "error"; ?>
我使用localhost/index.php
来运行,3个文件class.database.php
和class.users.php
dahsboard.php
位于目录中:classes
Mybe这是一个语法错误,但我找不到它。
我在phpmyadmin中创建了一个数据库并插入了数据。
任何人都可以帮助我吗?
答案 0 :(得分:1)
尝试将数据库连接更改为:
class Database
{
// Since you are calling this variable in other methods
// you need to make it available.
public $mysqli;
public function __construct()
{
$host = 'localhost';
$user = 'root';
$pass = 'password';
$name = 'usersystem';
$this->mysqli = new mysqli($host, $user, $pass, $name);
// You are mixing local with class-wide variables. Should all conform.
if ($this->mysqli->connect_errno)
echo "Failed to connect to MySQL: (".$this->mysqli->connect_errno.")".$this->mysqli->connect_error;
echo $this->mysqli->host_info."\n";
}
}
答案 1 :(得分:1)
您不能将$this
用于本地变量,它们需要是该类的属性,并且您需要一个公共连接,如下所示:
<?php
class Database {
public $mysqli;
private $host = 'localhost';
private $user = 'root';
private $pass = 'password';
private $name = 'usersystem';
public function __construct() {
$this->mysqli = new mysqli($this->host, $this->user, $this->pass, $this->name);
if ($this->mysqli->connect_errno) {
echo "Failed to connect to MySQL: (". $this->mysqli->connect_errno . ") ";
}else{
echo $this->mysqli->host_info . "\n";
}
}
}
?>
我注意到的另一件事是你在设置之前没有开始会话。 你也应该在重定向后退出
if($stmt->fetch()) {
session_start();
$_SESSION['username'] == $username;
header("Location: dashboard.php");
exit;
}
答案 2 :(得分:0)
在数据库的__construct方法中将$ user更改为$ this-&gt; user,$ host to $ this-&gt; host etc ..