我有以下查询:
List<Meeting> meetings =
(from m in crdb.tl_cr_Meetings
join p in crdb.tl_cr_Participants on m.MeetingID equals p.MeetingID
where p.TimeOut == null
select new Meeting
{
MeetingID = m.MeetingID,
MeetingName = m.MeetingName,
HostUserName = m.HostUsername,
BlueJeansMeetingID = m.tl_cr_BlueJeansAccount.MeetingID,
StartTime = m.StartTime,
Participants = (from pa in crdb.tl_cr_Participants
where pa.MeetingID == m.MeetingID
select pa.tl_cr_BlueJeansAccount.DisplayName).ToList()
}).Distinct().ToList();
我希望它能带回一份独特的会议清单。由于某种原因,它会为每个参与者带回一个条目,即使数据相同:
我错过了某个地方的分组吗?
修改
会议班目前非常基础:
public class Meeting
{
public int MeetingID { get; set; }
public string MeetingName { get; set; }
public string HostUserName { get; set; }
public DateTime StartTime { get; set; }
public List<string> Participants { get; set; }
public string BlueJeansMeetingID { get; set; }
}
答案 0 :(得分:2)
您可以使用juharr建议您的方式,或者您可以将比较器实现为实现IEqualityComparer接口的单独类,并将此比较器传递给distinct。
public class MeetingComparer : IEqualityComparer<Meeting>
{
public bool Equals (Meeting x, Meeting y)
{
return x.smth.Equals (y.smth);
}
public int GetHashCode (Meeting obj)
{
return obj.smth.GetHashCode ();
}
}
答案 1 :(得分:2)
我相信你为每个参与者获得一个条目的原因是你执行两个连接。 你需要做一个groupjoin。
var meetings = crdb.tl_cr_Meetings.GroupJoin(crdb.tl_cr_Participants,
k => k.MeetingID,
k => k.MeetingID,
(o,i) => new Meeting
{
MeetingID = o.MeetingID,
MeetingName = o.MeetingName,
HostUserName = o.HostUsername,
BlueJeansMeetingID = o.tl_cr_BlueJeansAccount.MeetingID,
StartTime = o.StartTime,
Participants = i.Select(s => s.DisplayName)
}).ToList();
答案 2 :(得分:1)
我认为您只需要删除代码的第3行(加入...)。
答案 3 :(得分:1)
这是Linq to Entities吗?无论如何,我会删除Distinct并添加一个组。
List<Meeting> meetings =
(from m in crdb.tl_cr_Meetings
join p in crdb.tl_cr_Participants on m.MeetingID equals p.MeetingID
where p.TimeOut == null
group m by new { m.MeetingID, m.MeetingName, m.HostUsername, MeetingID2 = m.tl_cr_BlueJeansAccount.MeetingID, m.StartTime } into m
select new Meeting
{
MeetingID = m.Key.MeetingID,
MeetingName = m.Key.MeetingName,
HostUserName = m.Key.HostUsername,
BlueJeansMeetingID = m.Key.MeetingID2,
StartTime = m.Key.StartTime,
Participants = (from pa in crdb.tl_cr_Participants
where pa.MeetingID == m.Key.MeetingID
select pa.tl_cr_BlueJeansAccount.DisplayName).ToList()
}).ToList();
答案 4 :(得分:1)
gabba解释了为什么你的代码失败了。通过以下方式,您可以使用群组联接重新查询查询,甚至不需要Distinct()
并使其看起来更干净:
from m in crdb.tl_cr_Meetings
join p in crdb.tl_cr_Participants on new { m.MeetingID, null }
equals new { p.MeetingID, p.TimeOut } into meetingParticipants
select new Meeting
{
MeetingID = m.MeetingID,
MeetingName = m.MeetingName,
HostUserName = m.HostUsername,
BlueJeansMeetingID = m.tl_cr_BlueJeansAccount.MeetingID,
StartTime = m.StartTime,
Participants = meetingParticipants
.Select(x => x.tl_cr_BlueJeansAccount.DisplayName)
.ToList()
}