Question

我是Android编程的新手。我正在使用不同类型的行在ListView上进行示例。我创建了一个从ArrayAdapter扩展的CustomAdapter

public class CustomAdapter extends ArrayAdapter<String> {
    public static final int TYPE_ODD = 0;
    public static final int TYPE_EVEN = 1;
    public static final int TYPE_WHITE = 2;
    public static final int TYPE_BLACK = 3;

    private final Context context;
    private final int resource;
    private ListViewItem[] objects;

    public CustomAdapter(Context context, int resource, ListViewItem[] objects) {
        super(context, resource, objects);
        this.context = context;
        this.resource = resource;
        this.objects = objects;
    }

Eclipse显示超级（上下文，资源，对象）; line as error“构造函数ArrayAdapter（Context，int，MainActivity.ListViewItem []）未定义”

我无法弄清楚为什么会这样。请帮忙。

Answer 1

尖括号（<String>）中的数据类型需要与您提供的数组中的数据类型匹配（ListViewItem[]）。在你的情况下，他们没有。

最有可能的是，你应该：

将其设为ArrayAdapter<ListViewItem>
删除private ListViewItem[] objects，因为它是不必要的并且会让您遇到麻烦 - 使用getItem()从超类访问数组

最有可能的是，你也不需要private final int resource，因为你不太可能会使用它，尽管我不能排除它。

Answer 2

public class CustomAdapter extends ArrayAdapter<ListViewItem> {
    public static final int TYPE_ODD = 0;
    public static final int TYPE_EVEN = 1;
    public static final int TYPE_WHITE = 2;
    public static final int TYPE_BLACK = 3;

    private final Context context;
    private final int resource;
    private ListViewItem[] objects;

    public CustomAdapter(Context context, int resource, ListViewItem[] objects) {
        super(context, resource, objects);
        this.context = context;
        this.resource = resource;
        this.objects = objects;
    }


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see the first line of answer just change this line

public class CustomAdapter extends ArrayAdapter<String>
to
public class CustomAdapter extends ArrayAdapter<ListViewItem>

构造函数ArrayAdapter <string>（Context，int，MainActivity.ListViewItem []）未定义</string>

2 个答案: