Question

我有2个阵列：

sentence []
keywords []

例如sentence []：

sentence [0] = "my car is blue"
sentence [1] = "the dog is sleeping"
sentence [2] = "I am in the kitchen"
sentence [3] = "How are you"

和keywords []：

keywords [0] = "my"
keywords [1] = " "
keywords [2] = "car"
keywords [3] = " "
keywords [4] = "is"
keywords [5] = " "
keywords [6] = "blue"
keywords [7] = "gghcxfkjc"
keywords [8] = "532jj"
keywords [9] = "How"
keywords [10] = " "
keywords [11] = "are"
keywords [12] = " "
keywords [13] = "you"
keywords [14] = " "
keywords [15] = "tech"

因此，例如，我需要检测“我的车是蓝色的”和“你好吗”是否在keywords数组中。请注意，关键字[]遵循句子的顺序。

如何在信息上进行比较和检测？

[编辑]我需要知道关键字[] 中匹配的每个单词的索引例如，第一句为0,1,2,3,4，另一句为9,10,11,12,13。

Answer 1

只需join个关键字并在结果字符串中查找句子：

kw = keywords.join("")
sentence.forEach(function(s) {
    console.log(s, kw.indexOf(s) >= 0);
});

打印

my car is blue true
the dog is sleeping false
I am in the kitchen false
How are you true

Answer 2

所以，你想循环遍历sentence，并检查关键词中是否有任何句子。

这就是诀窍：

// Build a big string of all keywords
var keyWordLine = keywords.join('').toLowerCase(); // "my car is bluegghcxfkjc532jjHow are you tech"
// Loop through all sentences
for(var i = 0; i < sentence; i++){
    // Check the current sentence
    if(keyWordLine.indexOf(sentence[i].toLowerCase()) !== -1){
        // sentence is in the keywords!
    }else{
        // sentence is not in the keywords!
    }
}

现在，您对这些结果的处理取决于您。例如，您可以构建一个仅包含keywords中出现的句子的数组：

var keywords = ["my", " ", "car", " ", "is", " ", "blue", "gghcxfkjc", "532jj", "How", " ", "are", " ", "you", " ", "tech"],
    sentence = ["my car is blue", "the dog is sleeping", "I am in the kitchen", "How are you"],
    keyWordLine = keywords.join('').toLowerCase(),
    output = [];
for(var i = 0; i < sentence; i++){
    if(keyWordLine.indexOf(sentence[i].toLowerCase()) !== -1){
         output.push(sentence[i]);
    }
}
alert(output);

JavaScript - 比较2个数组与空格分割

2 个答案: