Question

我需要能够每月显示所有周数，无论该周是否有几个小时。

改变这个：

2.00    2    July
2.25    3    July
7.25    5    July

对此：

0.00    1    July
2.00    2    July
2.25    3    July
0.00    4    July
7.25    5    July

以下是我正在使用的当前查询：

SELECT  SUM(te.Hours_Bill) AS HoursBilled
     ,  DATEPART(dd, DATEDIFF(dd, 0, te.Date_Start) / 7 * 7 ) / 7 + 1 AS HoursWeekNumber
     ,  DATENAME(mm, te.Date_Start) AS HoursMonthName

 FROM   AGR_Header ah
        INNER 
        JOIN Time_Entry te
          ON te.Agr_Header_RecID = ah.AGR_Header_RecID
        INNER 
        JOIN Company co
          ON co.Company_RecID = ah.Company_RecID

 WHERE  (te.Date_Start >= DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) -6, 0) AND te.Date_Start <= DATEADD(mm, DATEDIFF(mm, -1, GETDATE()) -1, -1))

 GROUP
    BY  DATEPART(dd, DATEDIFF(dd, 0, te.Date_Start) / 7 * 7 ) / 7 + 1
     ,  DATENAME(mm, te.Date_Start)
     ,  DATEPART(mm, te.Date_Start)

 ORDER
    BY  DATEPART(mm, te.Date_Start) ASC
     ,  DATEPART(dd, DATEDIFF(dd, 0, te.Date_Start) / 7 * 7 ) / 7 + 1 ASC

默认情况下，我想显示一个月的所有周数，如果一周没有结果，则显示0。

Answer 1

这可能对您有所帮助

CREATE TABLE #t
  (
     hr     NUMERIC(22, 6),
     weekno INT,
     mon    VARCHAR(20)
  )

INSERT INTO #t
VALUES
(2.00  ,  2 ,   'October'),
(2.25  ,  3  ,  'October'),
(7.25  ,  5  ,  'October')

WITH dates AS (
     SELECT 1 id,datename(month,(getdate())) mon
     UNION ALL
       SELECT  id+1, mon FROM dates WHERE id<5
)
SELECT Isnull(hr, 0) hrs,
       id    AS weekno,
       d.mon AS [month]
FROM   #t t
       RIGHT JOIN dates d
               ON t.mon = d.mon
                  AND t.weekno = d.id

输出

hrs       weekno    month
0.000000    1       October
2.000000    2       October
2.250000    3       October
0.000000    4       October
7.250000    5       October

总是显示空的周

1 个答案: