我正在尝试使用wp_mail和Ajax
在Wordpress中创建联系表单电子邮件有效,但我遇到了Ajax成功响应问题。
发送电子邮件后,我需要向用户显示电子邮件已发送的消息。
用于验证表单并显示成功消息的Javascript:
$atj(function(){
$atj('#training-submit').click(function(e) {
e.preventDefault();
e.stopPropagation();
if(verfiyFields()) {
alert('here');
requestData = {
'action' : 'myajax-submit',
'firstName' : $atj("#name").val(),
'email' : $atj("#email").val(),
}
$atj.post(MyAjax.ajaxurl, requestData).done(function(result){
result = jQuery.parseJSON( result );
console.log(result);
if(result == 'success'){
$atj('.training-form [type=text]').val('');
$atj('.training-form-message').append('<p class="training-form-complete-message">Thank you for the email</p>');
}
});
}
});
})
//Verfiy
function verfiyTrainingFields() {
var flag = true;
var name = $atj('#name');
var email = $atj('#email');
if(name.val().indexOf(' ') === -1 ){
name.parent().prepend('<p class="form-error">Please enter name, first space last</p>');
errorMessage($atj('.form-error'));
flag = false;
}
if(!IsEmail(email.val())){
email.parent().prepend('<p class="form-error">Please enter valid email address</p>');
errorMessage($atj('.form-error'));
flag = false;
}
return flag;
}
发送电子邮件并发送ajax响应的functions.php
文件。
function myajax_submit() {
$name = sanitize_text_field($_POST['firstName']);
$email = sanitize_text_field($_POST['email']);
$headers[] = 'From: ' . $name . ' <' . $email . '>' . "\r\n";
$headers[] = 'Content-type: text/html' . "\r\n"; //Enables HTML ContentType. Remove it for Plain Text Messages
$to = 'me@mysite.co.uk';
$message = 'Name: ' . $name . "\r\n" . 'email: ' . $email;
add_filter( 'wp_mail_content_type', 'set_html_content_type' );
wp_mail( $to, 'Email Test', $message );
remove_filter( 'wp_mail_content_type', 'set_html_content_type' );
echo 'email sent';
// generate the response
$response = json_encode( array( 'success') );
// response output
header( "Content-Type: application/json" );
echo $response;
exit;
}
发送电子邮件并发送'email sent'回显,但js中的if(result == 'success'){
无效。
js文件中的console.log(result)给出以下内容。
<br />
<b>Warning</b>: call_user_func_array() expects parameter 1 to be a valid callback, function 'set_html_content_type' not found or invalid function name in <b>/Users/user.name/Desktop/MAMP-DocRoot/appname/src/php/wp-includes/plugin.php</b> on line <b>192</b><br />
email sent<br />
<b>Warning</b>: Cannot modify header information - headers already sent by (output started at /Users/user.name/Desktop/MAMP-DocRoot/appname/src/php/wp-includes/plugin.php:192) in <b>/Users/user.name/Desktop/MAMP-DocRoot/appname/src/php/wp-content/themes/sitename/functions.php</b> on line <b>66</b><br />
["success"]
答案 0 :(得分:0)
您无法在回复后设置headers
。除掉
echo 'email sent';
答案 1 :(得分:0)
首先,删除echo
语句,因为它过早地发送标题。
然后,你需要明确地告诉jQuery帖子期待json:
$atj.post(MyAjax.ajaxurl, requestData).done(function(result){
result = jQuery.parseJSON( result );
console.log(result);
if(result == 'success'){
$atj('.training-form [type=text]').val('');
$atj('.training-form-message').append('<p class="training-form-complete-message">Thank you for the email</p>');
}
}, 'json' );
最后,您的json编码响应不会为您提供预期的response == success
。相反,请使用json_encode( array( 'success' => 1' ) );
并将您的javascript更改为:
if( 1 == result.success ) ){
}
这是一个完整的例子:
$.post( url, data, function( response ){
if( 1 == response.success ){
// Success - do something
} else {
// Failure
}
}, 'json' );
<?php
function myAjaxFunction(){
$result = array(
'success' => 0 // Assume failure first
);
if( $_POST[ 'whatever' ] == 'what i want' ){
$result[ 'success' ] = 1;
}
print json_encode( $result );
exit();
}