我需要替换数字字符。我的意思是我想用字符串中的bengali聊天替换english char。比方说,我有两个数组,
var enDigits = ["1", "2", "3", "4", "5", "6", "7", "8", "9", "0"]
和
var bnDigits = ["১", "২", "৩", "৪", "৫", "৬", "৭", "৮", "৯", "০"]
。
我在iOS&绝对是快速的。在PHP中,str_replace()
可以轻松完成。但是,我搜索并发现stringByReplacingOccurencesOfString
代表swift,但无法弄清楚是否可以使用数组。我需要你的建议。
答案 0 :(得分:4)
这是一个非常具体的答案,但如果您只是想要替换角色的字符,可以在源字符串上使用map
函数,如下所示:
let enDigits: [Character] = ["1", "2", "3", "4", "5", "6", "7", "8", "9", "0"]
let bnDigits: [Character] = ["১", "২", "৩", "৪", "৫", "৬", "৭", "৮", "৯", "০"]
let enString = "Jenny's number is 867-5309"
let bnString = String(map(enString, { ch in
if let index = find(enDigits, ch) {
return bnDigits[index]
}
return ch
}))
// Jenny's number is ৮৬৭-৫৩০৯
答案 1 :(得分:2)
如果您真的希望转换为孟加拉语数字,Cocoa提供了执行ICU transforms的API:
var string = "Jenny's number is 867-5309"
let transform = "[:Number:]; Any-Latin; Latin-Bengali"
let cfstr = NSMutableString(string: String(string)) as CFMutableString
var range = CFRangeMake(0, CFStringGetLength(cfstr))
CFStringTransform(cfstr, &range, ((transform as NSString) as CFString), 0)
println(cfstr) // Jenny's number is ৮৬৭-৫৩০৯