Question

我有以下文件夹结构：

WEB-INF /
- 页/
----针对home.jsp
---- admin.jsp
---- admin2.jsp
---- admin3.jsp

我有以下控制器@requestmapping：

@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView defaultPage() {

    ModelAndView model = new ModelAndView();
    model.setViewName("home");
    return model;

}

@RequestMapping(value = "/admin**", method = RequestMethod.GET)
public ModelAndView adminPage() {

    ModelAndView model = new ModelAndView();
    model.setViewName("admin");
    return model;

}

我需要第三个@Requestmapping for admin2.jsp？ admin3.jsp还有一个问题？等等？或者我可以将这些页面分组吗？

Answer 1

您只能有一个方法，它会根据某些逻辑返回不同的视图。

ModelAndView model;
if (some_condition) {
    model = new ModelAndView("admin");
}
else {
    model = new ModelAndView("admin2");
}
return model;

Answer 2

根据您的问题（“对网页进行分组”）我猜你想要在没有中间控制器的情况下快速映射到视图。

如果是这样的话就是答案（如果没有，请将其视为另一种选择）：

Java配置

@EnableWebMvc
@Configuration
public class AppConfig extends WebMvcConfigurerAdapter {

    /**
     * Here we register all direct mappings from URL directly to View Jsp
     * without the need to define an in-between controller.
     *
     * @param registry
     */
    @Override
    public void addViewControllers(ViewControllerRegistry registry) {
        registry.addViewController("/").setViewName("home");
        registry.addViewController("/admin").setViewName("admin");
        registry.addViewController("/admin2").setViewName("admin2");
        registry.addViewController("/admin").setViewName("admin3");
    }

   //assuming your view resolver here
   @Bean
    public ViewResolver viewResolver() {
        InternalResourceViewResolver resolver = new InternalResourceViewResolver();
        resolver.setPrefix("/WEB-INF/view/");
        resolver.setSuffix(".jsp");
        return resolver;
    }
   //..
}

XML配置

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" 
    xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans 
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd 
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

    <mvc:view-controller path="/" view-name="home" />
    <mvc:view-controller path="/admin" view-name="admin" />
    <mvc:view-controller path="/admin2" view-name="admin2" />
    <mvc:view-controller path="/admin3" view-name="admin3" />

<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
    <property name="prefix" value="/WEB-INF/view/"/>
    <property name="suffix" value=".jsp"/>
</bean>

</beans>

Answer 3

@RequestMapping(value="/admin{index}", method = RequestMethod.GET)
public ModelAndView adminPage(@PathVariable String index){

    return new ModelAndView("admin" + index);
}

您可以在您的情况下使用此代码，但我绝对不建议您这样做。最好为未来需求创建不同的控制器。

@RequestMapping用于多个页面

3 个答案: