Question

我有值存储在JSON url中并解析json中的值然后在app中显示。我使用Async任务从JSONArray获取值并显示在列表中。当我从服务器获取值时，我得到了错误，json值是

[{"name":"John","uuid":"B9407F30-F5F8-466E-AFF9-25556B57FE6D","major_id":"67889","minor_id":"7032","notification":"Welcome","type":"Website","website":"estimote.com"}]

日志：

10-16 17:46:38.996: W/System.err(11224): org.json.JSONException: Value [{"notification":"Welcome","uuid":"B9407F30-F5F8-466E-AFF9-25556B57FE6D","type":"Website","website":"estimote.com","major_id":"67889","minor_id":"7032","name":"John"}] at 0 of type org.json.JSONArray cannot be converted to JSONObject
10-16 17:46:38.996: W/System.err(11224):    at org.json.JSON.typeMismatch(JSON.java:100)
10-16 17:46:38.996: W/System.err(11224):    at org.json.JSONArray.getJSONObject(JSONArray.java:484)

代码：

protected Void doInBackground(Void... arg0) {
            // Creating service handler class instance
            ServiceHandler sh = new ServiceHandler();

            // Making a request to url and getting response
            String jsonStr = sh.makeServiceCall(url, ServiceHandler.GET);

            Log.d("Response: ", "> " + jsonStr);

            if (jsonStr != null) {
                try {
                    //JSONObject jsonObj = new JSONObject(jsonStr);

                    JSONArray jarray = new JSONArray(jsonStr);

                      jObject = jarray.getJSONObject(0);

                    Log.d("jsonObj_Response: ", "> " + jarray);

                    // Getting JSON Array node
                    contacts = jObject.getJSONArray(TAG_CONTACTS);

                    // looping through All Contacts
                    for (int i = 0; i < contacts.length(); i++) {
                        JSONObject c = contacts.getJSONObject(i);

                        //TAG_ID, TAG_NAME, TAG_major_id, TAG_minor_id, TAG_notification, TAG_type

                        String id = c.getString(TAG_ID);
                        String name = c.getString(TAG_NAME);
                        String email = c.getString(TAG_major_id);
                        String address = c.getString(TAG_minor_id);
                        String gender = c.getString(TAG_notification);



                        // tmp hashmap for single contact
                        HashMap<String, String> contact = new HashMap<String, String>();

                        // adding each child node to HashMap key => value
                        contact.put(TAG_ID, id);
                        contact.put(TAG_NAME, name);
                        contact.put(TAG_major_id, email);
                        contact.put(TAG_minor_id, address);

                        // adding contact to contact list
                        contactList.add(contact);
                    }

Answer 1

你错过了一个JSONArray

  JSONArray jarray = new JSONArray(jsonStr);
  for (int i = 0; i < jarray.length(); i++) {
        JSONArray innerArray = jarray.optJSONArray(i);
        for (int j = 0; j < innerArray.length(); j++) {
              jObject = innerArray.getJSONObject(j);
         }
  }

在OP的编辑

之后

  JSONArray jarray = new JSONArray(jsonStr);
  for (int i = 0; i < jarray.length(); i++) {
        JSONObject jobj = jarray.optJSONObject(i);
        if (jobj != null) {

        }
  }

Answer 2

jObject = jarray.getJSONObject（0）是一个JSONArray，你的字符串在数组中的数组中有一个对象;）

Answer 3

你有两个数组（＆＃34; [[＆＃34; /＆＃34;]]＆＃34;）所以＆＃34; jObject = jarray.getJSONObject（0）;＆＃34;失败，因为它试图转换＆＃34; [{＆＃34; name＆＃34; ... estimote.com＆＃34;}]＆＃34;到JSONObject但这是一个JSONArray。

Answer 4

jarray [0]是JSONarray而不是JSONObject。

Answer 5

我的解决方案如下，

 JSONArray arr = new JSONArray(jsonStr);//Response string is here

for (int i = 0; i < arr.length(); i++) {
    JSONArray arr2 = arr.optJSONArray(i);
    for (int j = 0; j < arr2.length(); j++) {
          jObject = arr2.getJSONObject(0);
     }
 }

在类型为org.json.JSONArray的0处无法转换为JSONObject

5 个答案: