Question

我需要检索所有row_id，如果其中一个值为AST = 'undefined'。

SELECT ROW_ID 
 FROM TABLE WHERE AST='unedefined'

不起作用。它只显示一行，但我希望获取具有相同ROW_ID的所有行。

这是我的表：

<TABLE BORDER="1">
<TR> <TH>ROW_ID</TH> <TH>GENDER2</TH> <TH>RelNum</TH> <TH>Date</TH> <TH>VALUE</TH> 
<TR> <TD>1</TD> <TD>M</TD> <TD>12</TD><TD>12/12/2014</TD><TD>undefined</TD>  
<TR> <TD>1</TD> <TD>M</TD> <TD>12</TD><TD>13/12/2014</TD><TD></TD>
<TR> <TD>2</TD> <TD>M</TD> <TD>45</TD><TD>12/12/2014</TD><TD>54</TD>
<TR> <TD>3</TD> <TD>M</TD> <TD>56</TD><TD>13/23/2024</TD><TD>999</TD>
<TR> <TD>3</TD> <TD>M</TD> <TD>56</TD><TD>12/12/2014</TD><TD>undefined</TD>
 </TABLE>
    And I only want to see this in return:
  
  <TABLE BORDER="1">
<TR> <TH>ROW_ID</TH> <TH>GENDER2</TH> <TH>RelNum</TH> <TH>Date</TH> <TH>VALUE</TH> 
<TR> <TD>1</TD> <TD>M</TD> <TD>12</TD><TD>12/12/2014</TD><TD>undefined</TD>  
<TR> <TD>1</TD> <TD>M</TD> <TD>12</TD><TD>13/12/2014</TD><TD></TD>
<TR> <TD>3</TD> <TD>M</TD> <TD>56</TD><TD>13/23/2024</TD><TD>999</TD>
<TR> <TD>3</TD> <TD>M</TD> <TD>56</TD><TD>12/12/2014</TD><TD>undefined</TD>

Answer 1

select  * 
from    table 
where   row_id in (
        select  row_id 
        from table 
        where ast = 'undefined')

Answer 2

select *
from table t
where exists
(
  select 1
  from table t2
  where t2.row_id = t.row_id
    and t2.ast = 'undefined'
);

在列中选择具有特定值的row_id

2 个答案: