我使用PDO将JSON数组存储在mysql TEXT字段中。 （以json_encode()编码）
获得数据后，如果我执行json_decode，结果为NULL。
似乎PDO正在取代每一个＆＃34;与"。
我已经多次使用过PDO和JSON，但这是我第一次遇到这个问题，所以我不明白发生了什么。
我在PHP 5.4.4上
此外，JSON随AJAX一起发送，以供您参考
谢谢，如果你能提供帮助。
表格中的JSON示例：
{"type_voie":"BD","indice_repetition":"T","num_voie":"121","nom_voie":"NOM_RUE","infos_voie":"NOM_RUE2","distribution_speciale":"BP789","cp":"34000","ville":"MONTPELLIER","bureau_distributeur":""}
我真正看到的var_dump：
{"type_voie":"BD","indice_repetition":"T","num_voie":"121","nom_voie":"NOM_RUE","infos_voie":"NOM_RUE2","distribution_speciale":"BP789","cp":"34000","ville":"MONTPELLIER","bureau_distributeur":""}
使用准备好的查询
插入检索数据的代码：
$formDataSQL = '
SELECT * FROM '.$this->prefix.'
WHERE formalite_id = '.$this->proc_id.'
';
$formDataReq = self::$db->prepare($formDataSQL);
$formDataReq->execute();
$formData = $formDataReq->fetch(PDO::FETCH_ASSOC);
然后在JSON字段上：
$addrData = json_decode(str_replace('"', '"', $champ['value']), true); // WORKING BUT NOT MAINTAINABLE
$addrData = json_decode($champ['value'], true); // NOT WORKING => NULL + JSON ERROR = JSON_ERROR_SYNTAX
以下是我的插入代码的简化示例：
foreach($saveData['personne_physique'] as $field => $value){
if(is_array($value)) $value = json_encode($value);
$param = ':'.$field;
$fields .= $field.'='.$param.', ';
$values[$param] = $value;
}
$fields = trim($fields, ', ');
$persPhysSQL = "UPDATE personne_physique SET $fields WHERE personne_id = ".$this->id;
$persPhysReq = self::$db->prepare($persPhysSQL);
$persPhysReq->execute($values);
以下是我的联系方式：
$host = 'mysql:dbname='.BDD_NAME.';host='.BDD_HOST.';charset=utf8';
$user = BDD_USER;
$pass = BDD_PASS;
$db = new PDO($host, $user, $pass, array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8") );
这很奇怪:(
答案 0 :(得分：0)
以下是基于您的数据示例的示例脚本：
<?php
try {
$Connection = new PDO('mysql:host=localhost;dbname=testing', USER, PASS);
$Connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}catch(PDOException $e){
echo 'Unable to connect to database' . "\n";
}
$id = $argv[1];
try {
$data = $Connection->prepare('SELECT * FROM `stackoverflow_26399231` WHERE ID = :id');
$data->bindParam(':id', $id, PDO::PARAM_INT);
$data->execute();
while($row = $data->fetch(PDO::FETCH_OBJ)){
print_r($row);
print_r(json_decode($row->data));
}
$Connection = null;
}catch(PDOException $e){
echo 'Error executing query: ' . $e->getMessage() . "\n";
}
?>
数据库表如下所示：
*************************** 1. row ***************************
id: 1
data: {"type_voie":"BD","indice_repetition":"T","num_voie":"121","nom_voie":"NOM_RUE","infos_voie":"NOM_RUE2","distribution_speciale":"BP789","cp":"34000","ville":"MONTPELLIER","bureau_distributeur":""}
在CLI中运行脚本时，您会收到回复：
stdClass Object (
[id] => 1
[data] => {"type_voie":"BD","indice_repetition":"T","num_voie":"121","nom_voie":"NOM_RUE","infos_voie":"NOM_RUE2","distribution_speciale":"BP789","cp":"34000","ville":"MONTPELLIER","bureau_distributeur":""}
)
stdClass Object (
[type_voie] => BD
[indice_repetition] => T
[num_voie] => 121
[nom_voie] => NOM_RUE
[infos_voie] => NOM_RUE2
[distribution_speciale] => BP789
[cp] => 34000
[ville] => MONTPELLIER
[bureau_distributeur] =>
)
我的脚本与您的脚本有何不同？我无法重现这个问题。
<强>更新
我的更新脚本遵循您的示例：
try {
$Connection = new PDO('mysql:host=localhost;dbname=testing', USER, PASS);
$Connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}catch(PDOException $e){
echo 'Unable to connect to database' . "\n";
}
$id = $argv[1];
$ary = array(
'foo' => 'bar',
'bar' => 'foo',
'a' => 'b',
'c' => 'd',
'e' => 'f'
);
try {
$fields = 'data=:data';
$values = array('data' => json_encode($ary));
$update = $Connection->prepare("UPDATE `stackoverflow_26399231` SET $fields WHERE ID = $id");
$update->execute($values);
$Connection = null;
}catch(PDOException $e){
echo 'Error executing query: ' . $e->getMessage() . "\n";
}
使用相同的脚本如上所述接收但是从PDO :: FETCH_OBJ更改为PDO :: FETCH_ASSOC作为您正在使用的内容，我得到此输出：
Array
(
[id] => 1
[data] => {"foo":"bar","bar":"foo","a":"b","c":"d","e":"f"}
)
stdClass Object
(
[foo] => bar
[bar] => foo
[a] => b
[c] => d
[e] => f
)
所以我仍然无法重现你所拥有的问题。两个脚本之间必须有不同的东西。