Question

我做了很多搜索，并试图自己写。我想写一个SQL查询来计算重复条目的数量，然后将重复条目的数量添加到可用的第一个条目的数量。这是我正在努力的游戏。

第一个条目是要显示的第一个CustomerID，ItemID，Var1。因为我们需要对这3个字段进行排序。

重复条目是ItemID和Var1相同的地方，然后我们要添加将重复记录的数量添加到第一条记录。库存ID对此不以为然，因为它是主键。我们无法添加具有不同CustomerID

的记录

列是

CREATE TABLE [dbo].[UsersInventory]
     ( [InventoryID] bigint NOT NULL IDENTITY(1,1),
       [CustomerID]  int NOT NULL ,
       [CharID] int NOT NULL DEFAULT ((0)) ,
       [BackpackSlot] int NOT NULL DEFAULT ((0)),
       [ItemID] int NOT NULL,
       [LeasedUntil] datetime NOT NULL,
       [Quantity] int NOT NULL DEFAULT ((1)),
       [Var1] int NOT NULL DEFAULT ((-1)),
       [Var2] int NOT NULL DEFAULT ((-1)),
       [Durability] int NULL )

Answer 1

试试这个：

create table T1 as (
select t1.*,count(*)-1 as records_quantity from T t1 group by t1.CustomerID,t1.ItemID,t1.Var1);

delete from T;

insert into T (select * from T1);

Answer 2

根据您对问题的描述，听起来您需要类似下面代码的内容。

实质上，您需要先计算所有唯一项目的总和，然后删除所有重复项，最后更新剩余项目的数量

-- Temporary table to hold the sums
declare @tempSum table
      ( CustomerID int,
        ItemID int,
        Var1   int,
        InventoryID int,
        Quantity    int )

-- Get the sum of quantity per Customer, Item and Var1
-- This also get the first InvetoryID, assuming that the smallest number is the first one
insert @tempSum
     ( CustomerID,
       ItemID,
       Var1,
       InventoryID,
       Quantity )
select CustomerID,
       ItemID,
       Var1,
       min(InventoryID),
       sum(Quantity)
  from UsersInventory
 group by CustomerID,
          ItemID,
          Var1

begin transaction
  -- Remove duplicate items
  delete usi
    from UsersInventory usi
           join
         @tempSum       tmp on tmp.CustomerID   = usi.CustomerID
                           and tmp.ItemID       = usi.ItemID
                           and tmp.Var1         = usi.Var1
                           and tmp.InventoryID <> usi.InventoryID -- This ensures all items get deleted that are didn't mark as our firsts

  -- Update the quantity that we summed earlier
  update usi
     set Quantity = tmp.Quantity
    from UsersInventory usi
           join
        @tempSum        tmp on tmp.CustomerID  = usi.CustomerID
                           and tmp.ItemID      = usi.ItemID
                           and tmp.Var1        = usi.Var1
                           and tmp.InventoryID = usi.InventoryID

commit transaction

计算SQL中的重复记录，然后将重复记录的数量添加到记录数量并删除其余记录

2 个答案: