Question

我有一个JSON字符串，我编码然后附加到REST URL。但问题是由于请求未经过某些特殊字符。我的JSON字符串如下

{"empName":"Jammy","fromDateRaw":"06-11-2014 ","fromDate":"Fri May 06 00:00:00 IST 12","travelRequestNumber":"2000070293","toDate":"Sun May 06 00:00:00 IST 36","mobileNumber":"","requestedOn":"Thu Oct 16 00:52:17 IST 2014","comments":"Employee prefer the following hotel and room type:Residence Inn Dallas Addison/Quorum Drive 14975 Quorum Drive?Dallas, Texas 75254 USA"}

即使我正在对网址进行编码，但由于最后一个网址没有通过，所以＃34;评论＆＃34;它有3个特殊字符，它们是＆＃34;：/？＆＃34;。如果我删除这三个字符并对此URL进行编码并将其附加到REST API，则会通过。但我需要这些角色，任何想法如何逃脱这些角色？

Answer 1

您应该使用URLEncoder类来编码您计划附加到网址的文字，例如：

String text = ""; // Insert your text here
String encoded = URLEncoder.encode(text, "UTF-8");

URLEncoder正确转义所有特殊字符，您可以安全地将encoded附加到网址字符串。

应用于您的字符串：

请注意，如果在Java源代码中指定了输入，则必须转义引号（使用\"）。

    String text = "{\"empName\":\"Jammy\",\"fromDateRaw\":\"06-11-2014 \",\"fromDate\":\"Fri May 06 00:00:00 IST 12\",\"travelRequestNumber\":\"2000070293\",\"toDate\":\"Sun May 06 00:00:00 IST 36\",\"mobileNumber\":\"\",\"requestedOn\":\"Thu Oct 16 00:52:17 IST 2014\",\"comments\":\"Employee prefer the following hotel and room type:Residence Inn Dallas Addison/Quorum Drive 14975 Quorum Drive?Dallas, Texas 75254 USA\"}";
    String encoded = URLEncoder.encode(text, "UTF-8");
    System.out.println(encoded);

输出：

%7B%22empName%22%3A%22Jammy%22%2C%22fromDateRaw%22%3A%2206-11-2014+%22%2C%22fromDate%22%3A%22Fri+May+06+00%3A00%3A00+IST+12%22%2C%22travelRequestNumber%22%3A%222000070293%22%2C%22toDate%22%3A%22Sun+May+06+00%3A00%3A00+IST+36%22%2C%22mobileNumber%22%3A%22%22%2C%22requestedOn%22%3A%22Thu+Oct+16+00%3A52%3A17+IST+2014%22%2C%22comments%22%3A%22Employee+prefer+the+following+hotel+and+room+type%3AResidence+Inn+Dallas+Addison%2FQuorum+Drive+14975+Quorum+Drive%3FDallas%2C+Texas+75254+USA%22%7D

您可以将其附加到以下网址：

URL url = new URL("http://somehost.com/something?data=" + encoded);

即使在编码后也无法访问URL

1 个答案: