如何在Drupal中将表单值推送到数据库

时间:2014-10-15 23:38:31

标签: php mysql drupal drupal-7

我正在构建一个drupal站点,我希望管理员能够将目标输入到drupal数据库的表中,然后可以输出给其他用户完成。

创建输入和表格的表单,但是在按下提交时,值不会添加到表格中,我不确定原因。

我从我连接到我的网站的模块中获得以下代码。我认为问题发生在我创建字段的顶部,或者在我提交值时在底部。我真的不确定。

谁能告诉我哪里出错了以及如何解决?

<?php

function achievementList_init() {
if(!(db_table_exists('achievements'))) {
    $achvmnt_list_schema = array(
        'description' => 'Achievement Fields',
        'fields' => array (
            'achvmntID' => array('type' => 'int', 'unsigned' => TRUE, 'AUTO_INCREMENT' => TRUE, 'not null' => TRUE),

            'achvmntName' => array('type' => 'varchar', 'length' => 256, 'not null' => TRUE, 'default' => ''),

            'achvmntDesc' => array('type' => 'varchar', 'length' => 256, 'not null' => TRUE, 'default' => ''),

            'achvmntPts' => array('type' => 'int', 'unsigned' => TRUE, 'not null' => TRUE),

    ));
    db_create_table('achievements', $achvmnt_list_schema);
}
}

function achievementList_menu($form, &$form_state) {
$items = array();
$items['achievementList/addAchievement'] = array(
    'title' => 'Achievement Input',
    'description' => 'Input Achievement info to add achievement to database',
    'page callback' =>'drupal_get_form',
    'page arguments' => array('achievementList_form'),
    'access callback' => TRUE
);
return $items;
}

function achievementList_form($form, &$form_state) {
$form['name'] = array (
    '#type' => 'textfield',
    '#title' => 'Achievement Name',
    '#size' => '20',
    '#maxlength' => '20',
    '#required' => TRUE
);
$form['description'] = array(
    '#type' => 'textfield',
    '#title' => 'Achievement Description',
    '#size' => 50,
    '#maxLength' => 400,
    '#required' => TRUE

);
$form['points'] = array(
    '#type' => 'textfield',
    '#title' => 'Point Award',
    '#size' => '20',
    '#maxlength' => '20',
    '#required' => TRUE
);
$form['add_button'] = array(
    '#type' => 'submit',
    '#value' => t('Add Achievement')
);
return $form;
}

function achievementList_validate($form, &$form_state) {
$name = $form_state['values']['name'];

if($form_state['values']['name'] = '') {
    form_set_error('name', t('Achievement must have a name!'));
}
if($form_state['values']['description'] = '') {
    form_set_error('name', t('Please describe the achievement!'));
}
if(!($form_state['values']['points'] > 0)) {
    form_set_error('name', t('Achievement must be worth points!'));
}
}

function achievementList_submit($form, &$form_state) {
db_insert('achievements')
->fields(array(
'achvmntName' => $form_state['values']['name'],
'achvmntDesc' => $form_state['values']['description'],
'achvmntPts' => $form_state['values']['points'],
))
->execute();
}

1 个答案:

答案 0 :(得分:1)

  • 您应该在“.install”文件中的HOOK_SCHEMA下添加SQL表创建代码。
  • 启用模块确认后,您在mysql下创建了表 根据要求。
  • 之后您的代码应该可以正常工作。[删除SQL表创建代码 来自HOOK_INIT]

您可以参考Drupal Example module

干杯!!!