Question

对于我的中期项目我创建一个随机生成数字的程序，并提示用户减去数字并输入他们的答案，同样在代码中，我想跟踪他们当前的分数，但由于某种原因分数没有更新，所有代码都在哪里

#include <iostream>
#include <ctime>
#include <cstdlib>

using namespace std;

int main()
{
A:

srand(time(0));

int number1 = rand() % 10;
int number2 = rand() % 10;
int answer;
int correctAnswer;
int score = 0;

if (number1 < number2)
{
    int temp = 0;
    temp = number2;
    number2 = number1;
    number1 = temp;
}


system("CLS");
cout << "Current Score: " << score << endl;
cout << "----------------------------------------------------" << endl;
cout << "What is " << number1 << " - " << number2 << " = ";
cin >> answer;

correctAnswer = number1 - number2;

if (answer == correctAnswer)
{
    cout << "Good Job!" << endl;
    score = score + 1;
    system("Pause");
    goto A;
} 
else 
{
    cout << "Incorrect. The Correct Answer is " << correctAnswer <<endl; 
    cout << "Try Again" << endl;
    score = (score * 0);
    goto A;
}


system("PAUSE");
return 0;
}

Answer 1

您的GOTO声明会将您发送到您设置得分= 0的程序顶部...这就是您没有看到分数增加的原因。

移动以下行：

int score = 0;

在“A：”标签上方。

Answer 2

首先要做的事情：不要使用goto。它通常不被认为是良好的做法，可以使您的代码无法维护。其次，您正在goto中初始化变量，因此在打印之前每次传递都设置为0.

#include <iostream>
#include <ctime>
#include <cstdlib>

using namespace std;

int main()
{
int score = 0;

A:

srand(time(0));

int number1 = rand() % 10;
int number2 = rand() % 10;
int answer;
int correctAnswer;


if (number1 < number2)
{
    int temp = 0;
    temp = number2;
    number2 = number1;
    number1 = temp;
}


system("CLS");
cout << "Current Score: " << score << endl;
cout << "----------------------------------------------------" << endl;
cout << "What is " << number1 << " - " << number2 << " = ";
cin >> answer;

correctAnswer = number1 - number2;

if (answer == correctAnswer)
{
    cout << "Good Job!" << endl;
    score = score + 1;
    system("Pause");
    goto A;
} 
else 
{
    cout << "Incorrect. The Correct Answer is " << correctAnswer <<endl; 
    cout << "Try Again" << endl;
    score = (score * 0);
    goto A;
}


system("PAUSE");
return 0;
}

需要C ++帮助，分数保持代码不能正常工作

2 个答案: