Question

此SQL Server查询正常工作

SELECT 
    dbo.sem_computer.COMPUTER_ID, COUNT(dbo.sem_computer.COMPUTER_ID) as Duplicate_Hardware_IDs
FROM
    dbo.sem_computer, [dbo].[V_SEM_COMPUTER], dbo.SEM_CLIENT, dbo.SEM_AGENT, dbo.IDENTITY_MAP
WHERE 
    sem_computer.COMPUTER_ID = [dbo].[V_SEM_COMPUTER].COMPUTER_ID
    and sem_computer.COMPUTER_ID = dbo.SEM_CLIENT.COMPUTER_ID
    and sem_computer.COMPUTER_ID = dbo.SEM_AGENT.COMPUTER_ID
    and dbo.SEM_CLIENT.GROUP_ID = IDENTITY_MAP.ID
    and dbo.SEM_AGENT.TIME_STAMP > DATEDIFF(second, '19700101', DATEADD(day, -1, GETDATE()))  *      CAST(1000 as bigint)
GROUP BY dbo.sem_computer.COMPUTER_ID
HAVING COUNT(dbo.sem_computer.COMPUTER_ID) > 1
ORDER BY Duplicate_Hardware_IDs DESC;

但是我想要SELECT个附加列（以显示哪些计算机有重复COMPUTER_ID）

SELECT 
    dbo.sem_computer.COMPUTER_NAME
,   [IP_ADDR1_TEXT]
,   dbo.SEM_AGENT.AGENT_VERSION
,   dbo.sem_computer.COMPUTER_ID, COUNT(dbo.sem_computer.COMPUTER_ID) as Duplicate_Hardware_IDs
FROM
    dbo.sem_computer, [dbo].[V_SEM_COMPUTER], dbo.SEM_CLIENT, dbo.SEM_AGENT, dbo.IDENTITY_MAP
WHERE 
    sem_computer.COMPUTER_ID = [dbo].[V_SEM_COMPUTER].COMPUTER_ID
    and sem_computer.COMPUTER_ID = dbo.SEM_CLIENT.COMPUTER_ID
    and sem_computer.COMPUTER_ID = dbo.SEM_AGENT.COMPUTER_ID
    and dbo.SEM_CLIENT.GROUP_ID = IDENTITY_MAP.ID
    and dbo.SEM_AGENT.TIME_STAMP > DATEDIFF(second, '19700101', DATEADD(day, -1, GETDATE()))  *      CAST(1000 as bigint)
GROUP BY dbo.sem_computer.COMPUTER_ID
HAVING COUNT(dbo.sem_computer.COMPUTER_ID) > 1
ORDER BY Duplicate_Hardware_IDs DESC;

我收到错误

专栏＆＃39; dbo.sem_computer.COMPUTER_NAME＆＃39;在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。

如何解决？

更新：执行时

SELECT 
    dbo.sem_computer.COMPUTER_NAME
,   [IP_ADDR1_TEXT]
,   dbo.SEM_AGENT.AGENT_VERSION
,   dbo.sem_computer.COMPUTER_ID, COUNT(dbo.sem_computer.COMPUTER_ID) as Duplicate_Hardware_IDs
FROM
    dbo.sem_computer, [dbo].[V_SEM_COMPUTER], dbo.SEM_CLIENT, dbo.SEM_AGENT, dbo.IDENTITY_MAP
WHERE 
    sem_computer.COMPUTER_ID = [dbo].[V_SEM_COMPUTER].COMPUTER_ID
    and sem_computer.COMPUTER_ID = dbo.SEM_CLIENT.COMPUTER_ID
    and sem_computer.COMPUTER_ID = dbo.SEM_AGENT.COMPUTER_ID
    and dbo.SEM_CLIENT.GROUP_ID = IDENTITY_MAP.ID
    and dbo.SEM_AGENT.TIME_STAMP > DATEDIFF(second, '19700101', DATEADD(day, -1, GETDATE()))  *      CAST(1000 as bigint)
GROUP BY dbo.sem_computer.COMPUTER_NAME,[IP_ADDR1_TEXT], dbo.SEM_AGENT.AGENT_VERSION, dbo.sem_computer.COMPUTER_ID
HAVING COUNT(dbo.sem_computer.COMPUTER_ID) > 1
ORDER BY Duplicate_Hardware_IDs DESC;

导致

COMPUTER_NAME   IP_ADDR1_TEXT    AGENT_VERSION    COMPUTER_ID          Duplicate_Hardware_IDs
ABC             10.10.10.10       12.1             56604FEE0AF              3

但我正在寻找

COMPUTER_NAME   IP_ADDR1_TEXT    AGENT_VERSION    COMPUTER_ID          Duplicate_Hardware_IDs
ABC             10.10.10.10      12.1               56604FEE0AF             3
123             10.10.10.15      12.2               56604FEE0AF             3
XYZ             10.10.10.25      12.2               56604FEE0AF             3

更新2 ：

我添加了FROM和WHERE

Answer 1

;WITH CTE AS
(
    SELECT  dbo.sem_computer.COMPUTER_NAME,
            [IP_ADDR1_TEXT],
            dbo.SEM_AGENT.AGENT_VERSION,
            dbo.sem_computer.COMPUTER_ID, 
            N = COUNT(*) OVER(PARTITION BY dbo.sem_computer.COMPUTER_ID)
    FROM
    ...
    WHERE 
    ...
)
SELECT *
FROM CTE
WHERE N > 1
ORDER BY N DESC

Answer 2

只需将Select列表中的列添加到Group By列表

即可

SELECT 
    dbo.sem_computer.COMPUTER_NAME
,   [IP_ADDR1_TEXT]
,   dbo.SEM_AGENT.AGENT_VERSION
,   dbo.sem_computer.COMPUTER_ID, COUNT(dbo.sem_computer.COMPUTER_ID) as Duplicate_Hardware_IDs
FROM
...
WHERE 
...
GROUP BY 
     dbo.sem_computer.COMPUTER_ID, 
     dbo.sem_computer.COMPUTER_NAME,
     ...
HAVING COUNT(dbo.sem_computer.COMPUTER_ID) > 1
ORDER BY Duplicate_Hardware_IDs DESC;`

Answer 3

任何在select语句中但不在任何聚合函数（MIN，MAX，SUM，COUNT，AVG）中的列都应该包含在GROUP BY子句中。

   SELECT 
         dbo.sem_computer.COMPUTER_NAME
        ,[IP_ADDR1_TEXT]
        ,dbo.SEM_AGENT.AGENT_VERSION
        ,dbo.sem_computer.COMPUTER_ID
        ,COUNT(dbo.sem_computer.COMPUTER_ID) as Duplicate_Hardware_IDs
    FROM
    ...
    WHERE 
    ...
    GROUP BY dbo.sem_computer.COMPUTER_NAME
            ,[IP_ADDR1_TEXT]
            ,dbo.SEM_AGENT.AGENT_VERSION
            ,dbo.sem_computer.COMPUTER_ID
    HAVING COUNT(dbo.sem_computer.COMPUTER_ID) > 1
    ORDER BY Duplicate_Hardware_IDs DESC;

Answer 4

您可以像其他人提到的那样在GROUP BY子句中添加列，或者如果您不希望使用这些列进行分组，请尝试以下

SELECT 
    dbo.sem_computer.COMPUTER_NAME,
    [IP_ADDR1_TEXT],
    dbo.SEM_AGENT.AGENT_VERSION,
    dbo.sem_computer.COMPUTER_ID, Duplicate_Hardware_IDs
FROM dbo.sem_computer c
INNER JOIN
dbo.SEM_AGENT ON //add the join conditions 
INNER JOIN 
(SELECT 
    dbo.sem_computer.COMPUTER_ID, COUNT(dbo.sem_computer.COMPUTER_ID) as Duplicate_Hardware_IDs
FROM
 ...
WHERE 
...
GROUP BY dbo.sem_computer.COMPUTER_ID
HAVING COUNT(dbo.sem_computer.COMPUTER_ID) > 1) temp
ON c.COMPUTER_ID=temp.COMPUTER_ID
ORDER BY Duplicate_Hardware_IDs DESC;

Answer 5

您必须在group by子句中添加所有非聚合字段： GROUP BY dbo.sem_computer.COMPUTER_NAME,[IP_ADDR1_TEXT] ,dbo.SEM_AGENT.AGENT_VERSION, dbo.sem_computer.COMPUTER_ID

SELECt dbo.sem_computer.COMPUTER_NAME,IP_ADDR1_TEXT,dbo.SEM_AGENT.AGENT_VERSION,dbo.sem_computer.COMPUTER_ID, COUNT(dbo.sem_computer.COMPUTER_ID) as Duplicate_Hardware_IDs FROM ... WHERE ...GROUP BY dbo.sem_computer.COMPUTER_NAME,IP_ADDR1_TEXT,dbo.SEM_AGENT.AGENT_VERSION, dbo.sem_computer.COMPUTER_ID HAVING COUNT(dbo.sem_computer.COMPUTER_ID) > 1ORDER BY Duplicate_Hardware_IDs DESc

Answer 6

很难从您的查询中了解到，因为您没有显示您如何将SEM_AGENT与查询相关联。

一个选项是将字段添加到组中 - 只需添加逗号和字段名称您还可以使用像LAST（）这样的聚合函数来返回查询中的字段。您也可以使用子选择返回该字段。不过，我不确定那个。

Answer 7

您可以通过加入两个查询来解决此问题。以下内容应该有效。

;WITH Duplicates AS (
    SELECT 
        sem_computer.COMPUTER_ID, 
        COUNT(sem_computer.COMPUTER_ID) as Duplicate_Hardware_IDs
    FROM
        sem_computer
    WHERE 
        ...
    GROUP BY sem_computer.COMPUTER_ID
)
SELECT 
    sem_computer.COMPUTER_NAME,
    sem_computer.[IP_ADDR1_TEXT],
    SEM_AGENT.AGENT_VERSION,
    sem_computer.COMPUTER_ID
FROM
        sem_computer
    INNER JOIN
        Duplicates
            ON sem_computer.COMPUTER_ID = Duplicates.COMPUTER_ID
    INNER JOIN
        SEM_AGENT
            ON SEM_AGENT.COMPUTER_ID = sem_computer.COMPUTER_ID
WHERE 
    Duplicates.Duplicate_Hardware_IDs > 1
ORDER BY Duplicate_Hardware_IDs DESC;

首先找到重复项，然后加入这些重复项并返回其他信息。您还必须加入SEM_AGENT表。

SELECT Count（）中的其他列

7 个答案: